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4 years ago

11

2. Using the following data, calculate the average atomic mass of magnesium (give your answer to the nearest

1 answer:

arlik [135]4 years ago

8 0

Answer:

24.32

Explanation:

From the question given above, the following data were obtained:

Isotope A:

Mass of A = 24

Abundance (A%) = 78.70%

Isotope B

Mass of B = 25

Abundance (B%) = 10.13%

Isotope C:

Mass of C = 26

Abundance (C%) = 11.17%

Average atomic mass of Mg =..?

The average atomic mass of Mg can be obtained as illustrated below:

Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] + [(Mass of C × C%)/100]

Average atomic mass = [(24 × 78.70)/100] + [(25 × 10.13)/100] + [(26 × 11.17)/100]

= 18.888 + 2.5325 + 2.9042

= 24.3247 ≈ 24.32

Therefore, the average atomic mass of magnesium (Mg) is 24.32

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The Glossopteris fossil is found in Australia, Antarctica, India, South Africa, and South America—all the southern continents. Now, the Glossopteris seed is known to be large and bulky and therefore could not have drifted or flown across the oceans to a separate continent

Explanation:

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4 years ago

A technical machinist is asked to build a cubical steel tank that will hold "265" L of water. Calculate in meters the smallest p

FrozenT [24]

Answer:

0.64 m

Explanation:

Given that;

1L = 0.001 cubic metre

Then;

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3 years ago

I need the answers? Pls help!

Vesnalui [34]

Im pretty sure its h2o so like the 2nd one

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3 years ago

Help! I’ll give brainliest if u get it right!

babunello [35]

Answer:

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3 years ago

A sodium hydroxide solution that contains 24.8 grams of NaOH per L of solution has a density of 1.15 g/mL. Calculate the molalit

poizon [28]

<u>Answer:</u> The molality of NaOH in the solution is 0.551 m

<u>Explanation:</u>

To calculate mass of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = 1.15 g/mL

Volume of solution = 1 L = 1000 mL (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$1.15 g/mL=\frac{\text{Mass of solution}}{1000mL}\\\\\text{Mass of solution}=(1.15g/mL\times 1000mL)=1150g$

We are given:

Mass of solute (NaOH) = 24.8 grams

Mass of solution = 1150 grams

Mass of solvent = Mass of solution - mass of solute = [1150 - 24.8] g = 1125.2 g

To calculate the molality of solution, we use the equation:

$Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

Where,

$m_{solute}$ = Given mass of solute (NaOH) = 24.8 g

$M_{solute}$ = Molar mass of solute (NaOH) = 40 g/mol

$W_{solvent}$ = Mass of solvent = 1125.2 g

Putting values in above equation, we get:

$\text{Molality of }NaOH=\frac{24.8\times 1000}{40\times 1125.2}\\\\\text{Molality of }NaOH=0.551m$

Hence, the molality of NaOH in the solution is 0.551 m

8 0

3 years ago