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Georgia [21]
3 years ago
7

Place the following in order of increasing F-A-F bond angle, where A represents the central atom in each molecule. PF3 OF2 PF4

Chemistry
1 answer:
iren2701 [21]3 years ago
8 0

Answer:

Correct option : B

Explanation:

First compare PF_3 with OF_2

there are two lone pair in OF_2 but only one lone pair presen in the PF_3 so more lone pair means more repulsion and hence less bond bond angle beacuse of lone pair repulsion bonded atom come closer and hence bond angle decreased .

bond angle inversely proporional to repulsion so more repulsion means less bond angle

bond \, angle \, :    OF_2 \textless PF_3

PF_4 does no exist it exist only in the form of PF_4^+ \, or\, PF_4^- and here assuming PF_4^+ because in case of PF_4^- difficult to compare bond angle because here two different type of bond angle is present.

Compare \, PF_3 \, and \, PF_4^+

there is no lone pair in the PF_4^+ so here will no be any repulsion and hence bond will be more in PF_4^+ as compared to PF_3

bond \, angle \, :    PF_3 \textless PF_4^+

bond \, angle \, :    OF_2 \textless PF_3 \textless PF_4^+

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