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harina [27]
3 years ago
8

How many neutrons exist in the isotope sodium-23?

Chemistry
2 answers:
Advocard [28]3 years ago
8 0
To find the number of neutrons, take the atomic mass minus the atomic number

the mass is given in the question as 23. the atomic number you can find in the periodic table for sodium, which is 11.

neutrons= 23 - 11= 12 neutrons
Nataliya [291]3 years ago
4 0
It has 12 neutrons in it.
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Answer:

A. 0.1 M

Explanation:

Given data

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  • Molar mass of NaI: 150 g/mol
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Step 1: Calculate the moles of solute

15g \times \frac{1mol}{150g} = 0.10mol

Step 2: Calculate the molarity of the solution

The molarity of the solution is equal to the moles of solute divided by the liters of solution.

M = \frac{0.10mol}{1L} =0.1M

The solution is 0.1 M.

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How many moles of NH3 would be formed from the complete reaction of 16.0 g H2?
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Taking into account the reaction stoichiometry, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

N₂ + 3 H₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

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The molar mass of the compounds is:

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Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • N₂: 1 mole ×14 g/mole= 14 grams
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<h3>Mass of NH₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 6 grams of H₂ form 2 moles of NH₃, 16 grams of H₂ form how many moles of NH₃?

moles of NH_{3}= \frac{16 grams of H_{2} x2moles of NH_{3}}{6 grams of H_{2}}

<u><em>moles of NH₃= 5.33 moles</em></u>

Then, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

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