24 decreased by the quotient and of a number 6 is -5

There are twenty classes at Northwestern Middle School and twenty classes at Southeastern Middle School. The number of students

Contact [7]

Answer:

The means and medians are not the same. Or B

Step-by-step explanation:

Hope this helped :)

7 0

2 years ago

Read 2 more answers

Evaluate the expression.

Firlakuza [10]

Step-by-step explanation:

the expression 5²=25

i hope this is helpful.

6 0

2 years ago

Connor have six employees and Bob 41 uniforms for them if you wanted to give them the same number of uniforms so he doesn't have

bagirrra123 [75]

It will be 6 to each person because 6x6 is 36 if u do 6x7 it will be 42 and it said 41 t-shirts not 42

6 0

3 years ago

Read 2 more answers

Please people i will give you lots of points and please give me the correct answer

cupoosta [38]

Answer:

15

Step-by-step explanation:

30 subtract 15 = 15 and both the 10 and the other 10 are the same

5 0

3 years ago

Gibbs Baby Food Company wishes to compare the weight gain of infants using its brand versus its competitor’s. A sample of 40 bab

Leviafan [203]

Answer:

$z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936$

The p value can be founded with this formula:

$p_v =P(z$

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

Step-by-step explanation:

Information given

$\bar X_{1}=7.6$ represent the mean for Gibbs products

$\bar X_{2}=8.1$ represent the mean for the competitor

$\sigma_{1}=2.3$ represent the population standard deviation for Gibbs

$\sigma_{2}=2.9$ represent the sample standard deviation for the competitor

$n_{1}=40$ sample size for the group Gibbs

$n_{2}=55$ sample size for the group competitor

$\alpha=0.05$ Significance level provided

z would represent the statistic

Hypothesis to verify

We want to check if babies using the Gibbs brand gained less weight, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}< 0$

The statistic would be given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

Replacing the info given we got:

$z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936$

The p value can be founded with this formula:

$p_v =P(z$

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

5 0

3 years ago