this is non linear because the rate of change is not constant.
3rd answer
Answer:
In words the answer is between t=0 and t=2.
In interval notation the answer is (0,2)
In inequality notation the answer is 0<t<2
Big note: You should make sure the function I use what you meant.
Step-by-step explanation:
I hope the function is h(t)=-16t^2+32t because that is how I'm going to interpret it.
So if we can find when the ball is on the ground or has hit the ground (this is when h=0) then we can find when it is in the air which is between those 2 numbers.
0=-16t^2+32t
0=-16t(t-2)
So at t=0 and t=2
So the ball is in the air between t=0 and t=2
Interval notation (0,2)
Inequality notation 0<t<2
1-(-4)^2
1-(-4 times -4)
1-(16)
1-16
-15
(1) [6pts] Let R be the relation {(0, 1), (1, 1), (1, 2), (2, 0), (2, 2), (3, 0)} defined on the set {0, 1, 2, 3}. Find the foll
goldenfox [79]
Answer:
Following are the solution to the given points:
Step-by-step explanation:
In point 1:
The Reflexive closure:
Relationship R reflexive closure becomes achieved with both the addition(a,a) to R Therefore, (a,a) is 
Thus, the reflexive closure: 
In point 2:
The Symmetric closure:
R relation symmetrically closes by adding(b,a) to R for each (a,b) of R Therefore, here (b,a) is:
Thus, the Symmetrical closure:
