If there's a graph with two lines, and it asks for a solution, the intersection point is always going to be the solution.
In this case the point is (4,0)
First, find the area of the circle A=pi r^2 = 3.14 (8)^2=200.96
the radius is half the diameter so r=16/2=8
Second, find the area of the triangle A=(hb)/2=(8*16)/2=64
since the triangle is resting on the diameter of the circle that means the height of the triangle is also the radius of the circle so h=8 and b=16
Third, subtract the area of the triangle from the area of the circle to find the area of the shaded regions.
so...
200.96-64=136.96
is the answer.
If Ken wants to pay more than 130, he needs to drive more than 90 miles. You subtract 94 from 130, which equals 36. 36 divided by .4 (for the price per mile) and it equals 90.
476.00×5%=23.80 tax=476+23.80=499.80
499.80×15%=74.97
499.80+74.97=574.77
4(5a-8) = 20a - 32. 20a - 32 + 2a = 22a - 32, which is not equal to 12a - 6. Mary is wrong.
