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GalinKa [24]
3 years ago
7

What is the slope of the line that passes through the points (-3, 15) and (-9, 7)?

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
7 0

m= y2 - y1 / x2 - x1

        7-15

m= -9 - (-3)

m= -8/-6

the answer is m=8/6

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Which number can each term of the equation be multiplied by to eliminate the fractions before solving?
Lerok [7]

To eliminate the fraction, we multiply by 4

<h3>How to eliminate the fractions?</h3>

The equation is given as:

-3/4m-1/2=2+1/4m

Rewrite properly as:

-\frac{3}{4}m - \frac 12 = 2 + \frac 14m

The denominators of the above fractions are 2 and 4

The LCM of 2 and 4 is 4

So, we multiply through by 4.

This gives

-3m - 2 = 8 + m

Hence, to eliminate the fraction, we multiply by 4

Read  more about fractions at:

brainly.com/question/10354322

#SPJ1

7 0
2 years ago
Find the height of the triangle.
Ierofanga [76]

Answer:

The value of x = 3.42

Step-by-step explanation:

Formula:

Sin ∅ = Opposite side /Hypotenuse

From the figure we can see a right angled triangle.

One angle is given, hypotenuse = 10 and height = x.

To find the value of x

sin 20 = Opposite side/hypotenuse = x/10

x = 10 * sin 20

 = 10 * 0.342 = 3.42

Therefore the value of x = 3.42

7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2
Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

but the integrand is even, so this is really just

\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

Substitute x = 1/2 arccot(u/2), which transforms the integral to

\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du

There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}

and it follows that

\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}

7 0
2 years ago
What's the cube root of 2744000
Paraphin [41]
The cube root of 2744000 is 140
4 0
4 years ago
Which of these debts could possibly be forgiven under Chapter 7 bankruptcy? A. Credit Card Debt B. Child Support C. Alimony D. A
a_sh-v [17]
Chapter 7 - Bankruptcy is a very beneficial means for those facing severe financial uncertainty or debts. And even though it cannot remove all your liability, it can help you eliminate a number of arrears so you can begin working to reestablish your credit score. These are the debts which are not forgiven in Chapter 7: student loans, child support, alimony payments, majority of taxes you owe and secured or collateral debts.

So the answer is A. Credit Card. A credit card debt can be forgiven under chapter 7 because it is the main reason why people file for bankruptcy just to discharge their credit card balance.
4 0
4 years ago
Read 2 more answers
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