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NISA [10]
3 years ago
9

Hi anyone indian here??​

Mathematics
2 answers:
MatroZZZ [7]3 years ago
4 0

yessssssssssssssssssssssssssssss

dem82 [27]3 years ago
3 0

Answer:

Nah I'm not lol

Step-by-step explanation:

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Is (a-3)(2a^2 + 3a + 3) equivalent to 2(a^3 - 1.5a^2 - 3a - 4.5)
vovikov84 [41]
<h3>Answer: Yes they are equivalent</h3>

==============================================

Work Shown:

Expand out the first expression to get

(a-3)(2a^2 + 3a + 3)

a(2a^2 + 3a + 3) - 3(2a^2 + 3a + 3)

2a^3 + 3a^2 + 3a - 6a^2 - 9a - 9

2a^3 + (3a^2-6a^2) + (3a-9a) - 9

2a^3 - 3a^2 - 6a - 9

Divide every term by 2 so we can pull out a 2 through the distributive property

2a^3 - 3a^2 - 6a - 9 = 2(a^3 - 1.5a^2 - 3a - 4.5)

This shows that (a-3)(2a^2 + 3a + 3) is equivalent to 2(a^3 - 1.5a^2 - 3a - 4.5)

4 0
3 years ago
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Snowcat [4.5K]
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3 years ago
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What is the smaller super script above the base that indicates how many times the
Alenkasestr [34]
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Write the expression below as a single logarithm in simplest form.<br> logo 7 – log, 7
Svet_ta [14]

Given:

The given expression is:

\log_b7-\log_b7

To find:

The single logarithm expression for the given expression.

Solution:

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We have,

\log_b7-\log_b7

Using quotient property of logarithm, we get

\log_b7-\log_b7=\log_b\left(\dfrac{7}{7}\right)

\log_b7-\log_b7=\log_b\left(1\right)

Therefore, the required expression is \log_b\left(1\right).

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4(-3) + 3(-5) + 7
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