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Kamila [148]
3 years ago
12

A company that sells widgets has to pay 1000 in one-time equipment fees and then it costs $\$0.50$ for each widget it makes. It

sells widgets at a price of $2.75 per widget. What is the least number of widgets the company has to sell in order to make a profit?
Mathematics
2 answers:
Alenkinab [10]3 years ago
6 0

Answer:

12 widgets

Step-by-step explanation:

IgorLugansk [536]3 years ago
5 0

Answer:

445

Step-by-step explanation:

\text{Profit}=\text{Price}-\text{Cost}\\\text{Profit}=2.75-50=2.25\\\text{In order to make back the starting amount we need to sell n lots of widgets.}\\2.25n\geq 1000\\n\geq \frac{1000}{2.25}\\n\geq 444.444444\\\text{You can't sell a fraction of products, so you need to round it up to the nearest number.}\\n=445

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HELP
babymother [125]

It's a isosceles right angled triangle

  • LJ=17
  • KL=10

\\ \sf{:}\Rrightarrow JK^2=17^2+10^2

\\ \sf{:}\Rrightarrow JK^2=289+100

\\ \sf{:}\Rrightarrow JK^2=389

\\ \sf{:}\Rrightarrow JK=19.72

4 0
2 years ago
What does x is greater than 5 mean
kotegsom [21]

Answer:

That  x is any number  bigger that 5 so 6 plus

Step-by-step explanation:

3 0
3 years ago
Rory rode his bike a total of 7.75 miles last week. He biked the same distance each of the 5 days he rode. How many miles did Ro
exis [7]

Answer:

Rory rode 1.55 miles each day

Step-by-step explanation:

7.75 divided by 5

6 0
2 years ago
In ΔIJK, k = 57 inches, i = 37 inches and ∠J=141°. Find ∠I, to the nearest degree.
Sonbull [250]

Answer:

<I= 15degrees

Step-by-step explanation:

Using the cosine rule formulae;

j² = i²+k²-2i cos <J

j² = 37²+57² - 2(37)(57)cos <141

j² = 1369+ 3249- 4218cos <141

j² = 4618- 4218cos <141

j² = 4618-(-3,278)

j²= 7,896

j = √7,896

j = 88.86inches

Next is to get <I

i² = j²+k²-2jk cos <I

37² = 88.86²+57² - 2(88.86)(57)cos <I

1369 = 7,896.0996+ 3249- 10,130.04cos <I

1369 = 11,145.0996 - 10,130.04cos <I

1369 - 11,145.0996 = - 10,130.04cos <I

-9,776.0996=- 10,130.04cos <I

cos <I =9,776.0996 /10,130.04

cos<I = 0.96506

<I = 15.19

<I= 15degrees

8 0
2 years ago
Consider the following system of equations:
Delicious77 [7]

Answer:

The system has infinitely solutions

Step-by-step explanation:

we have

-\frac{1}{3}x^{2}=-\frac{5}{6}+\frac{1}{3}y^{2}

\frac{1}{3}x^{2}+\frac{1}{3}y^{2}=\frac{5}{6}

Multiply by 3 both sides

x^{2}+y^{2}=\frac{5}{2} ----> equation A

The equation A is a circle centered at origin with radius r=\sqrt{5/2}\ units

and

5y^{2} =\frac{25}{2}-5x^{2}

5x^{2}+5y^{2} =\frac{25}{2}

Divide by 5 both sides

x^{2}+y^{2} =\frac{5}{2} ----> equation B

The equation B is a circle centered at origin with radius r=\sqrt{5/2}\ units

Equation A and Equation B are the same

Therefore

The system has infinitely solutions

7 0
3 years ago
Read 2 more answers
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