Considering the perimeter of the rectangle, we have that the length is of 9 inches and the width is of 55 inches.
<h3>What is the perimeter of a rectangle?</h3>
The perimeter of a rectangle of length l and width w is given as follows:
P = 2(l + w).
The length is an odd integer and the width is <u>5 times the next consecutive odd integer,</u> hence:
l = x, w = 5(x + 2).
The perimeter is of 128 inches, hence:
128 = 2l + 2w
128 = 2x + 10(x + 2)
128 = 2x + 10x + 20
12x = 108
x = 9.
Hence the length is of 9 inches and the width is of 55 inches.
More can be learned about the perimeter of a rectangle at brainly.com/question/10489198
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Answer:
35
Step-by-step explanation:
6 x 5 = 30
30 + 5 = 35
2x+38=50
2x+38-38=50 -38
2x =12
2x/2 =12/2
x=6
Answer:
9pi
Step-by-step explanation:
circumference is 2(pi)(r) or diameter(pi)
