Answer:
The horizontal distance from the plane to the person on the runway is 20408.16 ft.
Step-by-step explanation:
Consider the figure below,
Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°
BC is the horizontal distance from the plane to the person on the runway.
We have to find distance BC,
Using trigonometric ratio,
Here, 
,Perpendicular AB = 4000
Solving for BC, we get,
(approx)
(approx)
Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft
Responder:
$ 7540
Explicación paso a paso:
Dado que:
Kilogramos totales de papa = 6500
Número de kilogramos por paquete = 25
Precio por paquete = $ 30
La mitad se vendió a $ 30
El resto se vende a ($ 30 - $ 2)
Número total de paquetes de 25 kg:
6500 kg / 25 kg = 260 paquetes
Por lo tanto, paquete total = 260 paquetes
La mitad se vende a $ 30:
(260/2) * 30
130 * $ 30 = $ 3900
Resto vendido a $ 28:
(260 - 130) * $ 28
130 * $ 28 = $ 3640
Cantidad total realizada:
$ (3640 + 3900) = $ 7540
Answer:
X=3
Step-by-step explanation:
We have two linear functions which intersect at a point. This point is shown in the attached graph. Linear functions are lines which are made of points that satisfy the function or relationship. This means at the intersection, this point (3,-1), both functions have the same values. An input of x=3 produces y=-1 in both functions.
X= 1st integer
x+2= 2nd integer
x+4= 3rd integer
Add the integers together
x + (x + 2) + (x + 4)= 279
combine like terms
3x + 6= 279
subtract 6 from both sides
3x= 273
divide both sides by 3
x= 91 first integer
Substitute x=91 to find 2nd & 3rd integers
2nd Integer
=x+2
=91+2
=93
3rd Integer
=x+4
=91+4
=95
ANSWER: The three test scores are 91, 93 and 95.
Hope this helps! :)
