Answer:
18 and 15 i think
Step-by-step explanation:
Answer:
The probability that in a given day the store receives four or less bad checks is 0.70.
The probability that in a given day the store receives more than 3 bad checks is 0.50.
Step-by-step explanation:
The data provided shows the number of bad checks received by the management of a grocery store for a period of 200 days.
The probability distribution and the cumulative probability distribution are shown in the table attached below.
Let the number of bad checks received in a day be represented by <em>X</em>.
Compute the probability that in a given day the store receives four or less bad checks as follows:
P (X ≤ 4) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)

Thus, the probability that in a given day the store receives four or less bad checks is 0.70.
Compute the probability that in a given day the store receives more than 3 bad checks as follows:
P (X > 3) = 1 - P (X ≤ 3)
= 1 - [P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3)]
![=1-[0.04+0.06+0.10+0.30]\\=1-0.50\\=0.50](https://tex.z-dn.net/?f=%3D1-%5B0.04%2B0.06%2B0.10%2B0.30%5D%5C%5C%3D1-0.50%5C%5C%3D0.50)
Thus, the probability that in a given day the store receives more than 3 bad checks is 0.50.
X= 13 would be the answer
Answer:
Option D is correct.
The equation with roots 3 plus or minus square root 2 is x² - 6x + 7
Step-by-step explanation:
The roots of the unknown equation are
3 ± √2, that is, (3 + √2) and (3 - √2)
The equation can then be reconstructed by writing these roots as the solutions of the quadratic equation
x = (3 + √2) or x = (3 - √2)
The equation is this
[x - (3 + √2)] × [x - (3 - √2)]
(x - 3 - √2) × (x - 3 + √2)
x(x - 3 + √2) - 3(x - 3 + √2) - √2(x - 3 + √2)
= x² - 3x + x√2 - 3x + 9 - 3√2 - x√2 + 3√2 - 2
Collecting like terms
= x² - 3x - 3x + x√2 - x√2 - 3√2 + 3√2 + 9 - 2
= x² - 6x + 7
Hope this Helps!!!
Let First Sphere be the Original Sphere
its Radius be : r
We know that Surface Area of the Sphere is : 4π × (radius)²
⇒ Surface Area of the Original Sphere = 4πr²
Given : The Radius of Original Sphere is Doubled
Let the Sphere whose Radius is Doubled be New Sphere
⇒ Surface of the New Sphere = 4π × (2r)² = 4π × 4 × r²
But we know that : 4πr² is the Surface Area of Original Sphere
⇒ Surface of the New Sphere = 4 × Original Sphere
⇒ If the Radius the Sphere is Doubled, the Surface Area would be enlarged by factor : 4