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3 years ago

What is 3x+70=8x-20 show work

Mathematics

1 answer:

Elena-2011 [213]3 years ago

6 0

Answer:

Hi there!

Your answer is:

x= 18

Step-by-step explanation:

3x+70=8x-20

Isolate x on left side

3x+70=8x-20

-8x -8x

-5x +70 = -20

Isolate whole numbers on right side

-5x +70 = -20

-70 -70

-5x = -90

Isolate x by dividing both sides by -5

-5x = -90

/-5

x= 18

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The measurements of 11 fish caught during an angling competition are recorded.

stepladder [879]

Answer:

Step-by-step explanation:

A) = (35,?)

B) = POSITIVE

C) = 601

7 0

3 years ago

A stockbroker has kept a daily record of the value of a particular stock over the years and finds that prices of the stock form

amid [387]

Answer:

$12.43

Step-by-step explanation:

Given :

Mean = $8.52

Standard deviation, = $2.38

Stock price which falls beyond 0.05 of the distribution is at the 95th percentile

The 95th percentile distribution has a Pvalue of 1.645 (standard normal table)

We obtain the value of x, with z = 1.645

Using the Zscore relation :

Zscore = (score - mean) / standard deviation

1.645 = (score - 8.52) / 2.38

Cross multiply :

1.645 * 2.38 = score - 8.52

3.9151 = score - 8.52

Score = 8.52 + 3.9151

Score = $12.4351

Stock price beyond 0.05 is $12.43

8 0

3 years ago

There is a vendor at a carnival selling bags of cotton candy. Each bag of cotton candy has the same cost. She starts each day wi

umka21 [38]

Answer:

The cost of each cotton candy bag is $4.

Step-by-step explanation:

Consider the provided information.

Let, the vendor has $x$ dollar at the starting of each day.

Let, the cost of each cotton candy bag is $y$ .

Now when she sells a total of 12 bags, she has $128.

$x+12y=128$ .....(1)

After she sells a total of 20 bags, she has $160.

$x+20y=160$ ....(2)

Subtract equation 1 from equation 2.

$(x+20y)-(x+12y)=160-128$

$8y=32$

$y=4$

Hence, the cost of each cotton candy bag is $4.

6 0

3 years ago

Please help :) I have no clue & math isn’t my strong subject.

melisa1 [442]

Equation of a line that is perpendicular to given line is $y=\frac{-7}{4} x+\frac{7}{4}$ .

Equation of a line that is parallel to given line is $y=\frac{4}{7} x-\frac{69}{7}$ .

Solution:

Given line $y=\frac{4}{7} x+4$ .

Slope of this line, $m_1$ = $\frac{4}{7}$

$$\text{Slope of perpendicular line} = \frac{-1}{\text{Slope of the given line} }$

$$m_2=\frac{-1}{m_1}$

$$=\frac{-1}{\frac{4}{7} }$

Slope of perpendicular line, $m_2=\frac{-7}{4}$

Passes through the point (–7, 5). Here $x_1=-7, y_1=5$ .

Point-slope formula:

$y-y_1=m(x-x_1)$

$$y-(-7)=\frac{-7}{4} (x-5)$

$$y+7=\frac{-7}{4} x+\frac{35}{4}$

Subtract 7 from both sides, we get

$$y=\frac{-7}{4} x+\frac{7}{4}$

Equation of a line that is perpendicular to given line is $y=\frac{-7}{4} x+\frac{7}{4}$ .

To find the parallel line:

Slopes of parallel lines are equal.

$m_1=m_3$

$$m_3=\frac{4}{7}$

Passes through the point (–7, 5). Here $x_1=-7, y_1=5$ .

Point-slope formula:

$$y-(-7)=\frac{4}{7} (x-5)$

$$y+7=\frac{4}{7} x-\frac{20}{7}$

Subtract 7 from both sides,

$$y=\frac{4}{7} x-\frac{69}{7}$

Equation of a line that is parallel to given line is $y=\frac{4}{7} x-\frac{69}{7}$ .

7 0

3 years ago

MANY POINTS! PLEASE HELP

Vlad1618 [11]

Answer:

B. 51.7699^2

Step-by-step explanation:

Last 2 wrong because it is positive.

101.... is not the definite integral for the curve

51... purrfecto

3 0

2 years ago