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Tatiana [17]
3 years ago
12

Ada is putting autographed baseballs in a display case. The display can hold 28 baseballs, and there are already 17 baseballs in

the case. Ada thinks that she can display 9 more baseballs and the display case will be full. How can you use the equation 17 + b = 28 to check if she's right?
Mathematics
1 answer:
krok68 [10]3 years ago
8 0

Answer:

You can use the equation " 17 +b = 28 " to check is she's right because 17 +b has to be 28 baseballs.

Step-by-step explanation:

Sorry for that answer but what I meant was that 17 + b (How many baseballs can be added) must be 28. Now you can subtract both sides by 17 to isolate b by itself. When you do that you get b= 11. So you can add 11 more baseballs instead of 9, therefore she is wrong.

You can check this by putting 11 in for b in the equation. 17+11=28. This is correct.

Hopefully this helped you.

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By inspection we can see that <span>(1, 25), (2, 36), (3, 49), (4, 64), and (5, 81)

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3 years ago
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0.68 is a decimal and 68/100 or 68% is the percentage for 17/25.
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40 points fast For the following set of test scores, identify:
myrzilka [38]

Answer:

 The measure of center would this student want his teacher to use is the

median= {\bf 75}

Mean= {\bf 5}  ,  Mode={\bf 82}  , Range={\bf40}  and   Interquartile Range= {\bf 32}

Step-by-step explanation:

Given Data set= 50,55,70,75,82,82,90

Number of elements in data set= 7

To find Mean

The ‘Mean” is the average of a set of numbers.

The "Mean" is computed by adding all of the numbers in the data together and dividing by the number  of elements contained in the data set.

Mean= \frac{50 +55 +70 + 75 + 82 + 82 + 90} {7 }

Mean= \frac{504}{7}

Mean= 5

Median

The “Median” is the middle value of a set of ordered numbers.

Therefore Median=75

Mode

The "Mode" for a set of data is the value that occurs most often.

It is not uncommon for a data set to have more than one mode. This happens when two or more  elements occur with equal frequency in the data set.

Therefore Mode=82

Range

The "Range" is the difference between the largest value and smallest value in a set of data.

Range= 90-50

Range= 40

Interquartile Range

The “Interquartile Range” is the difference between smallest value and the largest value of the middle  50% of a set of data.

The "Interquartile Range" is from Q1 to Q3:

To find the interquartile range of a set of data:

The cut the list into four equal parts

. The quartiles are the “cuts”

The interquartile range is the distance between the two middle sets of data

Interquartile Range= Q_3-Q_1

Interquartile Range= 82-50

Interquartile Range= 32

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Answer:

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