Answer:
17 with a remainder of 25
Step-by-step explanation:
Answer:
<em>The correct answer is: False</em>
Step-by-step explanation:
<u>If the sum of the opposite angles in a quadrilateral is 180°</u>, then a circle can be circumscribed about the quadrilateral.
Here, ![\angle B+\angle D= 110\°+90\° = 180\°](https://tex.z-dn.net/?f=%5Cangle%20B%2B%5Cangle%20D%3D%20110%5C%C2%B0%2B90%5C%C2%B0%20%3D%20180%5C%C2%B0)
but, ![\angle A+\angle C= 70\°+90\°= 160\°](https://tex.z-dn.net/?f=%5Cangle%20A%2B%5Cangle%20C%3D%2070%5C%C2%B0%2B90%5C%C2%B0%3D%20160%5C%C2%B0)
So, a circle can't be circumscribed about the given quadrilateral.
A circle with a radius of 4cm sits inside a circle with a radius of 11cm
What is the area of the shaded region?
Round your final answer to the nearest hundredth.
Answer: 329.86 cm
A, b, d. Dilation is NOT <span>an </span><span>isometry</span>
Rules in adding fractions:
1) Make sure that they have common denominator.
5/10 + 3/10
2) Since both fraction have a denominator of 10, add the numerator and place the sum above the denominator
5/10 + 3/10 = (5 + 3)/10 = 8/10
3) Simplify the fraction
8/10 can still be simplified into 4/5
8 ÷ 2 = 4
10 ÷ 2 = 5
5/10 + 3/10 = 4/5