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ElenaW [278]
3 years ago
9

The consumption of a vegetable has decreased. The consumption per capita in 2000 was 22.8 ​pounds, and in​ 2010, the consumption

dropped to 12.1 pounds. Find the percent decrease. Round to the nearest tenth of a percent.
Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
5 0
So... if we take 22.8 to be the 100%, then it dropped to 12.1,
the difference in between being 22.8 - 12.1 or 10.7 decrease

so... what is 10.7 in percentage, of 22.8?
well
\bf \begin{array}{ccllll}
amount&\%\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
22.8&100\\
10.7&x
\end{array}\implies \cfrac{22.8}{10.7}=\cfrac{100}{x}

solve for "x"
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Answer:

Confidence interval = (4.61972, 25.46428)

Margin of Error = 3.9078675

Step-by-step explanation:

Given that :

This year:

Mean (μ1) = 64

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Sample size (n1) = 28

Last year:

Mean (μ2) = 48.958

Standard deviation (s2) = 15.4

Sample size (n2) = 28

99% confidence interval estimate of the difference μ1−μ2

α = 1 - 99% = 0.01

(μ1−μ2) ± t0.01,27 * (√s1²/n1 + s2²/n2)

t0.01, 27 = 2.770683 (t value calculator)

√s1²/n1 + s2²/n2 = √13.8^2/28 + 15.4^2/28 = 3.9078675

(64 - 48.958) ± 2.667(3.9078675)

15.042 ± 10.42228

(15.042 - 10.42228), (15.042 + 10.42228)

(4.61972, 25.46428)

The margin of error :

√(s1²/n1) + (s2²/n2)

√(13.8^2/28) + (15.4^2/28)

√(6.8014285 + 8.47)

√15.2714285

= 3.9078675

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7 0
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