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4 years ago

What do the elements highlighted in red have in common?

Chemistry

2 answers:

Scorpion4ik [409]4 years ago

6 0

The red elements are all in period 2

r-ruslan [8.4K]4 years ago

5 0

Answer:

The elements highlighted in red have in common the fact of belonging to the same period, which is period two. This makes electrons occupy up to level two.

Explanation:

In the periodic table you can distinguish horizontal divisions or rows called periods and vertical divisions or columns that are called groups.

The table is divided into periods that are listed from 1 to 7 from top to bottom. Elements that belong to the same period have different properties, but similar masses, because they have the same number of orbitals. That is, the elements of a given period are characterized by having electrons on the same outermost level, which is precisely the number that designates each period. For example, the elements of the third period have electrons up to level three. As the period number increases in the periodic table, the number of the energy level increases.

The elements highlighted in red have in common the fact of belonging to the same period, which is period two. This makes electrons occupy up to level two.

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Which of the following contains the smallest amount of matter

ioda

The answer is 25g. Let me know if you need an explanation

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3 years ago

For the reaction N2(g) + O2(g)2NO(g) H° = 181 kJ and S° = 24.9 J/K G° would be negative at temperatures (above, below) K. Enter

12345 [234]

ΔG deg will be negative above 7.27e+3 K.

Explanation:

The ΔG deg with the temperature can be found using the formula and the formula is given below
ΔG deg = ΔH deg - T ΔS deg
Given data, ΔH deg = 181kJ and ΔSdeg=24.9J/K
-T ΔS deg will be always negative and ΔG deg = ΔH deg will be positive and ΔG deg will be negative at relatively high temperatures and positive at relatively low temperatures
solving the equation and substitute ΔGdeg=0
ΔGdeg = ΔHdeg - T ΔSdeg
T= ΔHdeg/ΔSdeg
T=181 kJ / 2.49e-2 kJK-1
By simplification we get
T=7.27 × 10^3 K.
Therefore, Go will be negative above 7.27 × 10^3 K
Since ΔG deg = -RT lnK, when ΔGdeg < 0, K > 1 so the reaction will have K > 1 above 7.27 × 10^3 K.

ΔG deg will be negative above 7.27e+3 K.

7 0

3 years ago

Add electron dots and charges for the reaction of Ca and O

Nana76 [90]

The two atoms shown in the equation are CALCIUM and oxygen.

You start off with a neutral calcium atom with a shell of two electrons, a shell of 8 around that, a shell of 8 around that, and a shell containing 2...with no charge. 
20 protons + 20 electrons. 

You also have an oxygen atom with a shell of 2, and a shell of 6...with no charge. 
8 protons + 8 electrons. 

Each ionizes to form a calcium ion with 2 electrons removed (from the outer shell), leaving a +2 charge (20 protons, 18 electrons)... 
and an oxygen ion with 2 electrons added (to the outer shell), leaving a -2 charge (8 protons, 10 electrons). 

Their electrostatic attraction causes them to come together to form an ionic compound of CaO in a crystal lattice.

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4 years ago

Enter the Ksp expression for the solid AB2 in terms of the molar solubility x. AB2 has a molar solubility of 3.72×10−4 M. What i

AlekseyPX

Answer:

2.06 × 10⁻¹⁰

Explanation:

Let's consider the solution of a generic compound AB₂.

AB₂(s) ⇄ A²⁺(aq) + 2B⁻(aq)

We can relate the molar solubility (S) with the solubility product constant (Kps) using an ICE chart.

AB₂(s) ⇄ A²⁺(aq) + 2B⁻(aq)

I 0 0

C +S +2S

E S 2S

The solubility product constant is:

Kps = [A²⁺] × [B⁻]² = S × (2S)² = 4 × S³ = 4 × (3.72 × 10⁻⁴)³ = 2.06 × 10⁻¹⁰

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3 years ago

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andrezito [222]

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3 years ago