Your best answer for 1 is B.
A. 599 mg x 1g/1000mg x 1mole/174.24g = 0.003438 moles
<span>b. 0.003438 moles x 1000 mmoles/mole = 3.438 moles </span>
<span>c. 0.003438 moles/0.741 L = 0.0046 M </span>
<span>d. [K+] = 2 x 0.0046 = 0.0092 M because each mole K2 SO4 yields 2 moles K+ </span>
<span>e. [SO42-] = 0.0046 M </span>
<span>f. 599 mg/0.741 L = 808.4 mg/L = 808 ppm </span>
<span>g. 0.599g/741 ml x 100 ml = 0.08 g/100 ml = 0.08% w/v </span>
<span>h. pK+ = -log [K+] = -log 0.0092 = 2.04 </span>
<span>i. pSO42- = -log [SO42-] = -log 0.0046 = 2.34</span>
Answer:
13.5 %
Explanation:
First we<u> calculate the mass of 500 mL of water</u>, using <em>its density</em>:
- 500 mL * 1.00 g/mL = 500 g
Then we <u>calculate the mass percent of potassium sulfate</u>, using the formula:
Mass of Potassium Sulfate / Total Mass * 100%
- 78 g / (78 + 500) g * 100 % = 13.5 %