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serious [3.7K]
2 years ago
14

Make the range of the function f(x) =x^2+2x-1

Mathematics
1 answer:
Rashid [163]2 years ago
6 0
The range is Range:
[-2less than and equal to y]
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Find the area in blue.
barxatty [35]

Answer: The area  is 13\pift^2 or  40.84 ft^2

Step-by-step explanation:

First find the area of the square and subtract it from the area of the circle.

The area of a square is  one of the side length squared.

A= 6^2

A = 36  

Now find the area of the whole circle.As it indicates that the diameter is 14ft and to find the area of a circle,we need square the radius and multiply it by pi.

Since the diameter is 14 divide it by 2 to find the radius.  14/2 = 7  

A= 7^2*\pi  

A = 49\pi   We will leave the area in terms of pi.

49\pi - 36 = 13\pi

7 0
2 years ago
5+6 Lol I wanna help.
kati45 [8]

Answer:

11

Step-by-step explanation:

5+6 = 11

6 0
3 years ago
Find the integration of (1-cos2x)/(1+cos2x)
slega [8]

Given:

The expression is:

\dfrac{1-\cos 2x}{1+\cos 2x}

To find:

The integration of the given expression.

Solution:

We need to find the integration of \dfrac{1-\cos 2x}{1+\cos 2x}.

Let us consider,

I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx

I=\int \dfrac{2\sin^2x}{2\cos^2x}dx         [\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]

I=\int \dfrac{\sin^2x}{\cos^2x}dx

I=\int \tan^2xdx                      \left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]

It can be written as:

I=\int (\sec^2x-1)dx             [\because 1+\tan^2 \theta =\sec^2 \theta]

I=\int \sec^2xdx-\int 1dx

I=\tan x-x+C

Therefore, the integration of \dfrac{1-\cos 2x}{1+\cos 2x} is I=\tan x-x+C.

8 0
2 years ago
A rectangular prism is made of 81 unit cubes. The prism is 9 unit cubes long.
dimaraw [331]

Answer:

A width: 3 unit cubes

height 3 unit cubes

Step-by-step explanation:

Volume of rectangular prism = 81 unit cubes

l = Length of rectangular prism = 9 unit cubes

w = Width of rectangular prism

h = Height of rectangular prism

Volume of a rectangular prism is given by

V=lwh\\\Rightarrow 81=9wh\\\Rightarrow wh=\dfrac{81}{9}\\\Rightarrow wh=9

The product of width and height must be 9 so from the options this is only possible when width and height both are 3 units.

So, the width is 3 unit cubes and the height is 3 unit cubes.

4 0
2 years ago
These data show the age in years of 9 members of the youth orchestra. 12 14 16 17.5 10 18 15 15.5 19 What is the IQR (interquart
ryzh [129]
The interquartile range is 4.75.
8 0
3 years ago
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