Answer:
The values of y would be -9 and 15
Step-by-step explanation:
we know that
the formula to calculate the distance between two points is equal to
we have

S(-2,3) and T(3,y)
substitute the given values in the formula and solve for y
squared both sides
take square root both sides




therefore
The values of y would be -9 and 15
Answer:
<h3>A. y=-2x+3z+25</h3>
Step-by-step explanation:
Isolate the term of x and y from one side of the equation.
<u>To solve:</u>

<h3>2x+y-3z=25</h3>
<u>First, you have to subtract by 2x-3z from both sides.</u>

<u>Solve.</u>

- <u>Therefore, the correct answer is "A. y=-2x+3z+25".</u>
I hope this helps, let me know if you have any questions.
9514 1404 393
Answer:
a) 600
b) see below
c) 1.26 hours
Step-by-step explanation:
a) The value of y when x=0 is the coefficient of the exponential term:
y = 600·3^(-0) = 600·1 = 600
There were 600 atoms to start.
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b) see attached for a graph
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c) The graph shows 150 atoms at t = 1.26, about 1.26 hours after the start of time counting.
If you want to find that value algebraically, substitute for y and solve for x. Logarithms are involved.
150 = 600·3^(-x)
150/600 = 3^(-x)
log(1/4) = -x·log(3)
x = -log(1/4)/log(3) = log(4)/log(3) ≈ 1.2618595
After about 1.26 hours, there were 150 atoms.
Answer: its not 22 its 25
Step-by-step explanation: if it not correcnt than sorry wrong answer
OK, so the graph is a parabola, with points x=0,y=0; x=6,y=-9; and x=12,y=0
Because the roots of the equation are 0 and 12, we know the formula is therefore of the form
y = ax(x - 12), for some a
So put in x = 6
-9 = 6a(-6)
9 = 36a
a = 1/4
So the parabola has a curve y = x(x-12) / 4, which can also be written y = 0.25x² - 3x
The gradient of this is dy/dx = 0.5x - 3
The key property of a parabolic dish is that it focuses radio waves travelling parallel to the y axis to a single point. So we should arrive at the same focal point no matter what point we chose to look at. So we can pick any point we like - e.g. the point x = 4, y = -8
Gradient of the parabolic mirror at x = 4 is -1
So the gradient of the normal to the mirror at x = 4 is therefore 1.
Radio waves initially travelling vertically downwards are reflected about the normal - which has a gradient of 1, so they're reflected so that they are travelling horizontally. So they arrive parallel to the y axis, and leave parallel to the x axis.
So the focal point is at y = -8, i.e. 1 metre above the back of the dish.