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Lera25 [3.4K]
2 years ago
10

Jon decides to take his seven year old son to the movies. The price for the child's ticket is 3.75 dollars less than the price f

or the adult's ticket. If you represent the price for the child's ticket using the variable "x," how would you write the algebraic expression for the adult's ticket price? (1 point)
1. x + 3.75
2. 3.75x
3. x over 3.75
4. x3.75
Mathematics
1 answer:
Alecsey [184]2 years ago
7 0
<span>Price of the adult ticket is equal to the price of the child's ticket plus 3.75 or x+3.75</span>
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lord [1]

Answer:

(−1.5,1)

Step-by-step explanation:

Finding the distance, midpoint, slope, equation and the x y-intercepts of a line passing between the two points p1 (6,7) and p2 (-9,-5)

The distance (d) between two points (x1,y1) and (x2,y2) is given by the formula

d = √  ((X2-X1)2+(Y2-Y1)2)

d = √ (-9-6)2+(-5-7)2

d = √ ((-15)2+(-12)2)

d = √ (225+144)

d = √ 369

The distance between the points is 19.2093727122985

The midpoint of two points is given by the formula

Midpoint= ((X1+X2)/2,(Y1+Y2)/2)

Find the x value of the midpoint

Xm=(X1+X2)/2

Xm=(6+-9)/2=-1.5

Find the Y value of the midpoint

Ym=(Y1+Y2)/2

Ym=(7+-5)/2=1

The midpoint is: (-1.5,1)

6 0
3 years ago
Read 2 more answers
Solve for x. Evaluate and round your answer to 1 decimal place(tenths place). 10x=1200
Mandarinka [93]

Answer:

<h2>x = 3.1</h2>

Step-by-step explanation:

<h3>{10}^{x}  = 1200</h3>

<u>To solve first take logarithm to both sides</u>

That's

<h3>log_{10}(10) ^{x}  =  log_{10}(1200)</h3><h3 /><h3>log_{10}(10)^{x}  = x log_{10}(10)</h3>

But

<h3>log_{10}(10)  = 1</h3>

So we have

x =  log_{10}(1200)

<u>Write 1200 as a number with the factor 100</u>

That's

1200 = 100 × 12

So we have

<h3>x =  log_{10}(100 \times 12)</h3>

<u>Using the rules of logarithms</u>

That's

<h3>log_{a}(x \times y)  =  log_{a}(x)  +  log_{a}(y)</h3>

Rewrite the expression

That's

<h3>x =  log_{10}(100)  +  log_{10}(12)</h3><h3 /><h3>x =  log_{10}(10)^{2}  +  log_{10}(12)</h3><h3>x = 2 log_{10}(10)  +  log_{10}(12)</h3><h3>log_{10}(10)  = 1</h3><h3 /><h3>x = 2 +  log_{10}(12)</h3>

x = 3.079

So we have the final answer as

<h3>x = 3.1 to one decimal place</h3>

Hope this helps you

8 0
3 years ago
12<br> Using side lengths only, could the triangles be similar?<br> 0.5<br> m05 1 1.5
Murljashka [212]

Answer:

\large\boxed{\text{No.}\ \dfrac{0.5}{1}\neq\dfrac{1}{1.5}\neq\dfrac{1.5}{2}}

Step-by-step explanation:

\text{Let}\\ a,\ b,\ c\ -\ \text{sides of a triangle ABC, where}\ a\leq b\leq c\\d,\ e,\ f\ -\ \text{sides of a triangle}\ DE F,\ \text{where}\ d\leq e\leq f.\\\\\triangle ABC\sim\triangle DE F\iff\dfrac{a}{d}=\dfrac{b}{e}=\dfrac{c}{f}\\\\/\text{corresponding sides are in proportion}/

\bold{WARNING !!!}\\\\\text{No triangle like QRS exists!}\\\\1 + 0.5 = 1.5 !!!\\\\\text{The sum of the lengths of the two shorter sides of the triangle}\\\text{must be greater than the length of the longest side.}

\text{Despite this, let's check the ratios}

\text{We have:}\\\\\triangle XYZ\to a=1,\ b=1.5,\ c=2\\\triangle QRS\to d=0.5,\ e=1,\ f=1.5

\text{Check:}\\\\\dfrac{d}{a}=\dfrac{0.5}{1}=0.5\\\\\dfrac{e}{b}=\dfrac{1}{1.5}=\dfrac{10}{15}=\dfrac{2}{3}\\\\\dfrac{f}{c}=\dfrac{1.5}{2}=\dfrac{15}{20}=\dfrac{3}{4}\\\\\dfrac{d}{a}\neq\dfrac{e}{b}\neq\dfrac{f}{c}\neq\dfrac{d}{a}

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2 years ago
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DedPeter [7]

Answer:

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Step-by-step explanation:

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7 0
2 years ago
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sweet-ann [11.9K]

Answer: I belive it’s B. both are taxed at the federal and local level

Step-by-step explanation:

3 0
2 years ago
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