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kolezko [41]
3 years ago
6

Students experiment with the flow of

Chemistry
2 answers:
tatiyna3 years ago
7 0
A because it does not let electricity flow
OleMash [197]3 years ago
5 0
Rubber is not very good at conducting electricity. This is because rubber makes it difficult for electrons to flow between atoms, due to rubber having tightly packed electrons. Materials like rubber are known as insulators.
Conductors are the opposite, they conduct electricity very well. Examples of conductors are metal, which is why metal is used in wires.
Since rubber is not a conductor, answer choice B can be eliminated. This can also eliminate answer choice D, since insulators like rubber don't allow electricity to easily flow.
While rubber gloves keep our hands dry, there are no liquids involved in this experiment and this is not the main reason for using rubber gloves. This eliminates answer choice C.

The answer is A. rubber gloves are insulators.
The teacher instructs the students to wear rubber gloves to prevent them from getting an electric shock.

Answer:
A. rubber gloves are insulators

Hope this helps!
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7 0
2 years ago
A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 4250 mL of water at 2
Assoli18 [71]

Answer:

The specific heat of copper is 0.385 J/g°C

Explanation:

A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 425 mL of water at 22.55 degrees Celsius. The final temperature of the water was recorded to be 26.15 degrees Celsius. What is the specific heat of the copper?

Step 1: Data given

Mass of copper = 85.2 grams

Temperature of copper = 221.32 °C

Volume of water = 425 mL

Temperature of water = 22.55 °C

Final temperature = 26.15 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculat the specific heat of copper

Heat lost = heat gained

Q = m*c*ΔT

Qcopper = -Qwater

m(copper)*c(copper)*ΔT(copper) = - m(water) * c(water) * ΔT(water)

⇒ m(copper) = 85.2 grams

⇒ c(copper) = TO BE DETERMINED

⇒ ΔT(copper) = the change in temeprature = T2 -T1 = 26.15 -221.32 = -195.17 °C

⇒ m(water) = The mass of water = 425 mL * 1g/mL = 425 grams

⇒ c(water) = The specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature of water = 26.15 - 22.55 = 3.6

85.2 * c(copper) * (-195.17) = -425 * 4.184 * 3.6

c(copper) = 0.385 J/g°C

The specific heat of copper is 0.385 J/g°C

(Note, The original question says the volume of the water is 4250 mL. IF this is not an error, the specific heat of copper is 3.85 J/g°C (10x higher than the normal value).

8 0
3 years ago
Someone please help me with the second question ONLY
wlad13 [49]

Answer:

no

Explanation:

this experiment could not be replicated, because there are no specific measurements. the details would not be the same because it does not include the type of paper used nor the diameter, width or length. A guess of the measurements would be the only way to replicate this experiment but other then that, no you cannot.

4 0
3 years ago
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