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BartSMP [9]
3 years ago
15

The process of joining many small molecules into larger molecules is called(1) neutralization (3) saponification(2) polymerizati

on (4) substitution
Chemistry
2 answers:
yulyashka [42]3 years ago
8 0
(2) polymerization. polymerization<span> is a process of reacting monomer molecules together in a chemical reaction to form polymer chains or three-dimensional networks.</span>
fenix001 [56]3 years ago
5 0

Answer: polymerization.


Justification:


Poly means many, and monomer means parts.


Then, a polymer is a compound made of many smaller molecules, and the process to form a polymer is named polymerization.


Polymers are large molecules formed by the combination of of many repeated units (monomers).


Some polymerization reaction are adition and condensation.


Some very well know polymers are polyethilene, nylon, pvc, polyester, among many other. They are also known as plastics.

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Ethanol (c2h5oh) melts at -114°c. the enthalpy of fusion is 5.02 kj/mol. the specific heats of solid and liquid ethanol are 0.9
maria [59]
You'll want to add three amounts of heat. 

(1) Specific heat of lowering the temperature from -135°C to the melting point -114°C
(2) Latent heat of fusion/melting
(3) Specific heat of elevating the temperature from -114°C to -50°C

(1) E = mCΔT = (25 g)(0.97 J/g·°C)(1 kJ/1000 J)(-114 - -135) = 0.509 kJ
(2) E = mΔH = (25 g)(5.02 kJ/mol)(1 mol/46.07 g ethanol) = 2.724 kJ
(3) E = mCΔT = (25 g)(2.3 J/g·°C)(1 kJ/1000 J)(-50 - -114) = 3.68 kJ

<em>Summing up all energies, the answer is 6.913 kJ.</em>
7 0
3 years ago
Of the atoms below, __________ is the most electronegative.<br> PLZ HELP I'LL AWARD BRINLIEST.
Readme [11.4K]

Hello sir, The answer that you are looking for is fluorine. Fluorine is the most electronegative atom. I am also sorry for calling you sir. I didn't know you were a woman.

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3 years ago
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andre [41]

Answer: im not writting a pharaphraph. Buuuuuuuuuuuut... explian the type of reaction then explanie how that type of reaction works.

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6 0
3 years ago
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A sample of HI (9.30×10^−3mol) was placed in an empty 2.00 L container at 1000 K. After equilibrium was reached, the concentrati
Sedaia [141]

Answer:

The answer is "29.081"

Explanation:

when the empty 2.00 L container of 1000 kg, a sample of HI (9.30 x 10-3 mol) has also been placed.  

\text{calculating the initial HI}= \frac{mol}{V}

                                       =\frac{9.3 \times 10 ^ -3}{2}

                                      =0.00465 \ Mol

\text{Similarly}\ \  I_2 \ \  \text{follows} \ \  H_2 = 0 }

Its density of I 2 was 6.29x10-4 M if the balance had been obtained, then we have to get the intensity of equilibrium then:

HI  = 0.00465 - 2x\\\\ I_{2}  \ eq = H_2 \ eq = 0 + x \\\\

It is defined that:

I_2 = 6.29 \times 10^{-4}  \ M \\\\x = I_2 \\\\

HI \ eq= 0.00465 - 2x \\

          =0.00465 -2 \times 6.29 \times 10^{-4} \\\\ =  0.00465 -\frac{25.16 }{10^4}  \\\\   = 0.003392\  M

Now, we calculate the position:  

For the reaction H 2(g) + I 2(g)\rightleftharpoons  2HI(g), you can calculate the value of Kc at 1000 K.  

data expression for Kc

2HI \rightleftharpoons  H_2 + I_2 \\\\\to Kc = \frac{H_2 \times I_2}{HI^2}

         = \frac{6.29\times10^{-4} \times 6.29 \times 10^{-4}}{0.003392^2} \\\\= \frac{6.29\times 6.29 \times 10^{-8}}{0.003392^2} \\\\= \frac{39.564 \times 10^{-8}}{1.150 \times 10-5} \\\\= 0.034386

calculating the reverse reaction

H_2(g) + I_2(g)\rightleftharpoons  2HI(g)

Kc = \frac{1}{Kc} \\\\

     = \frac{1}{0.034386}\\ \\= 29.081\\

7 0
3 years ago
How many grams of chlorine are required to react with 5.00 moles of sodium to produce sodium chlorine?
Oduvanchick [21]

Answer:

2.5 mol Cl2 will react with 5 mol Na.

Explanation:

5 0
3 years ago
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