Answer:
9th grade student=33.3%, unit 7=45%
Step-by-step explanation:
I think it’s A because it’s not supplementary I’m not sure
We know that According to Algebra of Real Functions :
If f and g are two real functions which are defined under the same domain then 

Now we need find the Domain of this Function :
The Condition for Square Root to be defined is any Expression under it should be Greater than or Equal to Zero.
When Function is a Fraction, it Cannot be defined when the denominator becomes zero. Because when the denominator is zero, the fraction tends to ∞ (because anything divided by zero tends to ∞)
According to Above Conditions Described above, The Given Function is Definable only when the Expression which is under the Square Root is Greater than Zero and x ≠ 0
⇒ 3x - 9 > 0
⇒ 3x > 9
⇒ x > 3
⇒ The Domain of the Given Function is (3 , ∞)
1st Option is the Answer
First, we pass the other number subtracting, like this:

Then we pass the number 3 dividing, like this:

So, the answer is: W = -3.
Hope this helped! c:
Answer:
Assuming you mean 2+ (4/5), no
Step-by-step explanation:
=2* (5/5) + (4/5)
=10/5 + 4/5
=14/5
if you mean (2+4)/5,
its 6/5, so still not 1/3