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3 years ago

5

Belinda babysits her neighborhood's children in the evening every 14 days. Belinda goes to vist her grandmother in the afternoon

every 21 days. Belinda has both activitives planned for today. Will Belinda have bith activitives again on the same day within 30 days? Explain your answer.

2 answers:

noname [10]3 years ago

8 0

No unless she skips a day or the parents don't Need her to work or they go on vacation

Solnce55 [7]3 years ago

5 0

Answer:

No

Step-by-step explanation:

Belinda babysits her neighborhood's children in the evening every 14 days. Belinda goes to visit her grandmother in the afternoon every 21 days.

If Belinda has both activities planned for today.

The next time Belinda will have both activities on the same day is determined by the Lowest Common Multiples of 21 and 14.

Express each number as a product of its prime factors

21=3 X 7

14 =2 X 7

L.C.M = 2 X 3 X 7 =42

The next time she will have both activities on the same day is 42 days from today. So both activities occurring 30 days from now is impossible.

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Answer:

1) $2y^{2}+4y-9$

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Step-by-step explanation:

1) Distribute the negative sign that is outside the parentheses and then you must add like terms, as following:

$(y^{2}-3y-5)-(-y^{2}-7y+4)=y^{2}-3y-5+y^{2}+7y-4=2y^{2}+4y-9$

2) According to the Product property of exponents, when you multiply powers with the same base, you must add the exponents. Then:

$(6xy^{3}z)(3x^{2}yx^{2})=18x^{5}y^{4}z$

3) Apply the Distributive property and the Product property of exponents. Then, you obtain:

$-3x^{3}(-2x^{2}+4x-3)=6x^{5}-12x^{4}+9x^{3}$

4) $(4a+5)^{2}$ is a square of a sum, then, by definition you have:

$(a+b)^{2}=a^{2}+2ab+b^{2}$

Then:

$(4a+5)^{2}=(4a)^{2}+2(4a)(5)+5^{2}=16a^{2}+40a+25$

The coefficient of the second term is the number in front of the variable <em>a.</em> Then, the answer is: 40

5) Apply the Distributive property and the Product property of exponents, then, oyou must add the like terms:

$(x-4)(x^{2}-3x-9)=x^{3}-3x^{2}-9x-4x^{2}+12x+36=x^{3}-7x^{2}+3x+36$

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Answer:

$3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}$

Step-by-step explanation:

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