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Pachacha [2.7K]
3 years ago
11

Balanced equation for complete combustion

Chemistry
1 answer:
frosja888 [35]3 years ago
3 0
C3H8 + 5O2 = 3CO2 + 4H2O.
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Which statements describe situations where organisms interact and depend on each other for survival?
iragen [17]

Answer:

Mutualisms/Symbiotic relationships

Explanation:
It’s a mutual beneficial relationship that helps both sides… for example… clownfish and sea anemones. The sea anemones provide the clownfish protection and shelter, and the clownfish provides nutrients from waste for the anemones.

Hope that helped!

6 0
2 years ago
When methane is burned with oxygen, the products are carbon dioxide and water, If you produce 20 grams of water and 10 grams of
scZoUnD [109]
When methane is burned with oxygen, the products are carbon dioxide and water. If you produce 9 grams of water and 11 grams of carbon dioxide from 16 grams of oxygen, how many grams of methane were needed for the reaction? First you need to write a balanced chemical equation.
3 0
3 years ago
Read 2 more answers
Any change that alters a substance without changing it into another substance.
Ber [7]
A physical change.

Physical change = can be reverted + doesn't change substance
Chemical = changes substance
7 0
3 years ago
Copper(II) sulfide is oxidized b molecular oxygen to produce gaseous sulfur trioxide and solid copper (II) oxide. The gaseous pr
Tasya [4]

Explanation:

Copper(II) sulfide reacts with oxygen gas to give solid copper(II) oxide and sulfur trioxide gas.

The reaction is given as:

CuS+2O_2\rightarrow CuO(s)+SO_3(g)

When 1 mol copper(II) sulfide react with 2 moles of oxygen gas it gives 1 mol of solid copper(II) oxide and 1 mol of sulfur trioxide gas

The gas formed in above reaction that is sulfur trioxide reacts with water to give sulfuric acid or hydrogen sulfate.

The reaction is given as:

SO_3(g)+H_2O(l)\rightarrow H_2SO_4(aq)

1 mol of sulfur trioxide gas reacts with 1 mol of liquid water to produce 1 molo of liquid hydrogen sulfate or sulfuric acid

3 0
3 years ago
How much heat energy is required to raise the temperature of 0.360 kg of copper from 23.0 ∘C to 60.0 ∘C? The specific heat of co
AVprozaik [17]
MThe  heat  energy  required  to  raise  the  temperature   of  0.36Kg   of  copper   from   22 c   to  60  c  is  calculate  using  the  following  formula

MC delta T
m(mass)=  0.360kg  in  grams  =  0.360  x1000 = 360 g
  c(specific  heat  energy)  =  0.0920  cal/g.c
delta T =  60- 23  = 37  c

heat  energy is therefore=  360g   x0.0920 cal/g.c  x 37  c=  1225.44  cal

5 0
3 years ago
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