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12345 [234]
3 years ago
5

An isotope with a mass number of 193 has 116 neutrons. What is the atomic number of this

Chemistry
1 answer:
Zinaida [17]3 years ago
6 0

Answer:

Atomic number of this  isotope = 77

Explanation:

Given that,

Mass number = 193

No of neutrons = 116

We need to find the atomic no of this isotope.

We know that,

Atomic mass = No of protons + No. of neutrons

Also, atomic no = no of protons

So,

Atomic mass = atomic no + No. of neutrons

⇒ Atomic no = Atomic mass - no of neutrons

Atomic no = 193 - 116

Atomic no = 77

Hence, 77 is the atomic no of the isotope.

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When the reaction shown is correctly balanced, the coefficients are: kclo3 → kcl + o2?
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From the balanced equation 2KClO3 → 2KCl + 3O2, the coefficients are the following:
coefficient 2 in front of potassium chlorate KClO3
coefficient 2 in front of potassium chloride KCl 
coefficient 3 in front of oxygen molecule O2

We got this balanced equation by identifying the number of atoms of each element that we have in the given equation KClO3 → KCl + O2.
Looking at the subscripts of each atom on the reactant side and on the product side, we have
     KClO3 → KCl + O2
       K=1          K=1
       Cl=1         Cl=1
       O=3          O=2

We can see that the oxygens are not balanced. We add a coefficient 2 to the 3 oxygen atoms on the left side and another coefficient 3 to the 2 oxygen 
atoms on the right side to balance the oxygens:
     2KClO3 → KCl + 3O2
The coefficient 2 in front of potassium chlorate KClO3 multiplied by the subscript 3 of the oxygen atoms on the left side indicates 6 oxygen atoms just as the coefficient 3 multiplied by the subscript 2 on the right side indicates 6 oxygen atoms.

The number of potassium K atoms and chloride Cl atoms have changed as well:
     2KClO3 → KCl + 3O2
       K=2            K=1
       Cl=2          Cl=1
       O=6           O=6

We now have two potassium K atoms and two chloride Cl atoms on the reactant side, so we add a coefficient 2 to the potassium chloride KCl on the product side: 
     2KClO3 → 2KCl + 3O2, which is our final balanced equation.
        K=2           K=2
        Cl=2          Cl=2
        O=6           O=6
The potassium, chlorine, and oxygen atoms are now balanced.

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Answer:

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cupric bromide: CuBr₂ (oxidation number = +2)

cuprous bromide: CuBr (oxidation number = +1)

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