<u>Answer:</u>
Carbon (i) : quaternary carbon
Carbon (ii) : secondary carbon
Carbon (iii) : tertiary carbon
Carbon (iv) : secondary carbon
<u>Explanation:</u>
Carbons can be classified into 4 categories:
(1) Primary carbon
: These are the atoms where the carbon atom is attached to one other carbon atom.
(2) Secondary carbon
: These are the atoms where the carbon atom is attached to two other carbon atoms.
(3) Tertiary carbon
: These are the atoms where the carbon atom is attached to three other carbon atoms.
(4) Quaternary carbon
: These are the atoms where the carbon atom is attached to four other carbon atoms.
In the given structure:
Carbon (i) is attached to 4 further carbon atoms and hence, it is a quaternary carbon.
Carbon (ii) is attached to 2 further carbon atoms and hence, it is a secondary carbon.
Carbon (iii) is attached to 3 further carbon atoms and hence, it is a tertiary carbon.
Carbon (iv) is attached to 2 further carbon atoms and hence, it is a secondary carbon.
They are heated by the sun. Good luck :)
<span>The Answer </span>should be<span> .074 M</span>
Answer:
![74.64\ \text{g}](https://tex.z-dn.net/?f=74.64%5C%20%5Ctext%7Bg%7D)
Explanation:
Reactants
Magnesium = 24.3 g
Hydrogen chloride= x g
Products
Hydrogen gas = 2.04 g
Magnesium chloride = 96.9 g
As the mass of the reactions is conserved we have
Mass of reactants = Mass of products
![24.3+x=2.04+96.9\\\Rightarrow x=2.04+96.9-24.3\\\Rightarrow x=74.64\ \text{g}](https://tex.z-dn.net/?f=24.3%2Bx%3D2.04%2B96.9%5C%5C%5CRightarrow%20x%3D2.04%2B96.9-24.3%5C%5C%5CRightarrow%20x%3D74.64%5C%20%5Ctext%7Bg%7D)
Mass of hydrogen chloride is
.
<u>Answer:</u> The correct answer is 1.18 g.
<u>Explanation:</u>
We are given a chemical equation:
![C(S)+O2(g)\rightarrow CO_2(g)](https://tex.z-dn.net/?f=C%28S%29%2BO2%28g%29%5Crightarrow%20CO_2%28g%29)
We know that at STP conditions:
22.4L of volume is occupied by 1 mole of a gas.
So, 2.21L of carbon dioxide is occupied by =
of carbon dioxide gas.
By Stoichiometry of the above reaction:
1 mole of carbon dioxide gas is produced by 1 mole of carbon
So, 0.0986 moles of carbon dioxide is produced by =
of carbon.
Now, to calculate the mass of carbon, we use the equation:
![\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%7D%7D%7B%5Ctext%7BMolar%20mass%7D%7D)
Moles of carbon = 0.0986 mol
Molar mass of carbon = 12 g/mol
Putting values in above equation, we get:
![0.0986mol=\frac{\text{Mass of carbon}}{12g/mol}\\\\\text{Mass of carbon}=1.18g](https://tex.z-dn.net/?f=0.0986mol%3D%5Cfrac%7B%5Ctext%7BMass%20of%20carbon%7D%7D%7B12g%2Fmol%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20carbon%7D%3D1.18g)
Hence, the correct answer is 1.18 g.