Hello!
Let 'a' stand for adult tickets and 'c' for children tickets.
a + c = 15
(Both adult and children tickets make up a total of 15 tickets).
30a + 20c = 330
a = 3
c = 12
A N S W E R:
William bought 3 adults tickets and 12 children's tickets.
Mr. Mole's burrow was at an altitude of 6 meters below the ground.
Step-by-step explanation:
Step 1:
We need to determine the distance that Mr. Mole covers in a single minute.
To do that we divide the difference in values of altitude by the difference in the time periods.
For the first case, Mr. Mole had traveled -18 meters in 5 minutes.
We also have, he traveled -25.2 meters in 8 minutes.
Step 2:
The distance he covered in 1 minute
So with every minute, Mr. Mole digs down an additional 2.4 meters below the surface.
To determine where Mr. Mole's burrow is we subtract the distance traveled in 5 minutes from -18.
The altitude of Mr. Mole's burrow
So Mr. Mole's burrow was at an altitude of 6 meters below the ground i.e. -6 meters.
Answer:
IT would be B I believe
Step-by-step explanation:
f(x) = 3x + 391
1. -3x and -6x
2. 21 and -13
3. 21 and -13
4. -10b and 6b, 15 and -5
5. -20 and 30, 4c and -2c