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3 years ago

Please help me fast, best answer will get brainliest.

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

3 0

Answer:

Answer is below

Step-by-step explanation:

The outliers are 20 and 78 because they are not close to the other numbers. They have a great difference between them and the other numbers.

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What is the roots of the quadratic equation? 6x^2+5x-4=0

Rama09 [41]

x = $\frac{1}{2}$ or x = - $\frac{4}{3}$

consider the factors of the product 6 × - 4 = - 24 which sum to the coefficient of the x- term ( + 5)

the factors are + 8 and - 3 ( split the middle term using these factors

6x² - 3x + 8x - 4 = 0 ( factor by grouping )

3x(2x - 1) + 4(2x - 1 ) ( take out common factor of (2x - 1) )

= (2x - 1)(3x + 4) = 0

equate each factor to zero and solve for x

2x - 1 = 0 ⇒ x = $\frac{1}{2}$

3x + 4 = 0 ⇒ x = - $\frac{4}{3}$

4 0

3 years ago

Read 2 more answers

Find p(0),p(1),p(-1) and p(2) of the 3x(x-2) <br><br>

Effectus [21]

Answer:

$p(0)=(0)^{2}-3(0)+2$

→ $p(0)=0+0+2$

→ $p(0)=2$

$------$

<u>Replace x→-1</u>

$p(-1)=(-1) ^{2} -3 (-1)+2$

→ $p(-1)=1-3+2$

→ $p(-1)=0$

$----------$

<u>Now make x→2</u>

$p(2)=(2) ^{2} -3(2)+2$

→ $p(2)=4-6+2$

→ $p(2)=0$

$Answer:-2,0,0$

$-----------$

hope it helps...

have a great day!!

5 0

2 years ago

What is the area of the triangle?

Luda [366]

Answer:

270cm^2

Step-by-step explanation:

The side length is irrelevant and does not matter.

The area of a triangle is found by multiplying the base by the height and then dividing that by two.

For this problem it would be...

30*18=540

540/2=270

So the area would be 270cm^2

3 0

2 years ago

If a factory continuously dumps pollutants into a river at the rate of the quotient of the square root of t and 45 tons per day,

julsineya [31]

<h2>Hello!</h2>

The answer is:

The first option, the amount dumped after 5 days is 0.166 tons.

To solve the problem, we need to integrate the given expression and evaluate using the given time.

So, integrating we have:

$\int\limits^5_0 {\frac{\sqrt{t} }{45} } \, dt=\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \, dt\\\\\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \ dt=\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt\\\\\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt=(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)\\\\(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)=(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)$

$(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)=(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)\\\\(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)=(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)\\\\(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)=(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})\\\\(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})=\frac{2}{135}*11.18-0=0.1656=0.166$

Hence, we have that the amount dumped after 5 days is 0.166 tons.

Have a nice day!

5 0

3 years ago

What is the solution to the system of equations graphed below?

zhannawk [14.2K]

B. (-2,2)

The solution is where the two lines intersect

4 0

2 years ago

Please help me fast, best answer will get brainliest.​

Please help me fast, best answer will get brainliest.