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marshall27 [118]
2 years ago
15

There are 12 marbles in a bag, and the marbles are either yellow or green. Two marbles will be randomly picked from the bag, wit

hout replacing the first one picked. The probability that both marbles will be yellow is 5 33 . How many GREEN marbles are in the bag? A) 4 B) 5 C) 6 D) 7
Mathematics
1 answer:
Lisa [10]2 years ago
6 0

Answer: there are 7 green marbles in the bag

Step-by-step explanation:

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Graph the inequality X+2y>6
IceJOKER [234]
The line is supposed to be straight sorry mine is not straight I couldn’t find my ruler.

7 0
2 years ago
Obtain the required confidence interval for the difference between two population proportions. Assume that independent simple ra
Thepotemich [5.8K]

Answer:

The 95% confidence interval for the difference between the proportions of women and men who follow a regular exercise program = ( -0.293, 0.023)

Step-by-step explanation:

The formula for confidence interval for the difference between the proportions is given as:

p1 - p2 ± z × √p1 (1 - p1)/n1 + p2(1 - p2)/n2

From the question

We have two groups.

Group 1 = For women

A survey found that 37 of 74 randomly selected women

p1 = x/n1

n1 = 74

x1 = 37

p1 = 37/74

p1 = 0.5

Group 2 = For Men

A survey found out that 47 of 74 randomly selected men follow a regular exercise program

p2 = x/n1

n2= 74

x2 = 47

p2 = 47/74

p2 = 0.6351351351 ≈ 0.635

z = z score for 95% Confidence Interval = 1.96

The confidence interval for the difference between the proportions is given as:

p1 - p2 ± z × √p1 (1 - p1)/n1 + p2(1 - p2)/n2

0.5 - 0.635 ± 1.96 × √0.5 (1 - 0.5)/74 + 0.635(1 - 0.635)/74

-0.135 ± 1.96 × √(0.5 × 0.5)/74 + (0.635× 0.365)/74

-0.135 ± 1.96 × 0.08068750209663572

-0.135 ± 0.158147504109406

Hence:

= -0.135 - 0.158147504109406

= -0.2931475041

Approximately = -0.293

= -0.135 + 0.158147504109406

= 0.0231475041

Approximately = 0.023

Therefore, the 95% confidence interval for the difference between the proportions of women and men who follow a regular exercise program = ( -0.293, 0.023)

6 0
2 years ago
Can someone help me please
N76 [4]
26/100 or simplified to 13/50
7 0
2 years ago
Solve the equation on the interval [0,2pi] 5sec(x)+7=-3
vovangra [49]

Answer:

Hello,

x\in \bigg\{\dfrac{2\pi}{3} ,\dfrac{4\pi}{3}\bigg\}\\

Step-by-step explanation:

5*sec(x)+7=-3\\\\sec(x)=\dfrac{-10}{5} \\\\\dfrac{1}{cos(x)} =-2\\\\cos(x)=-\dfrac{1}{2} \\\\x=120^o\ or\ x=240^o\\

8 0
2 years ago
Read 2 more answers
A metallurgist has an alloy with 5% titanium and an alloy with 30% titanium. He needs 100 grams of an alloy with 15% titanium. H
andrey2020 [161]
Let us convert the percentages to decimal format first.. so 5% is just 5/100 or 0.05 and 15% is just 15/100 or 0.15

so hmmm, so, let's say it needs "x" amount and "y" amount of each respectively, so, whatever "x" and "y" are, they must add up to 100, and whatever their concentration is, must add up to what the mixture yields

thus

\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{5\% alloy}&x&0.05&0.05x\\
\textit{30\% alloy}&y&0.30&0.3y\\
-----&-----&-------&-------\\
mixture&100&0.15&15
\end{array}
\\\\\\
\begin{cases}
x+y=100\implies \boxed{y}=100-x\\
0.05x+0.3y=15\\
----------\\
0.5x+0.3\left( \boxed{100-x} \right)=15
\end{cases}

solve for "x"

what's "y"? well, y = 100 - x
4 0
3 years ago
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