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2 years ago

What is the range of the function f(x) = (x – 1)2 when the domain is {-5, 0, 5}?

Mathematics

1 answer:

Bas_tet [7]2 years ago

5 0

9514 1404 393

Answer:

{1, 16, 36}

Step-by-step explanation:

Put the numbers in for x and see what the f(x)-values are.

(-5-1)^2 = (-6)^2 = 36

(0-1)^2 = (-1)^2 = 1

(5-1)^2 = 4^2 = 16

The range is the set of values {1, 16, 36}.

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CaHeK987 [17]

I believe you add 2.42 and 1.72

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3 years ago

Read 2 more answers

Here are two sets of numbers, a and b. Set a :200,104,100,160. Set b: 270,400,483,300, x. Mean of set a: mean of set b= 3:8. Wor

LenKa [72]

Given:

The given sets are:

Set a : 200, 104, 100, 160.

Set b: 270, 400, 483, 300, x.

Mean of set a: mean of set b= 3:8

To find:

The value of x.

Solution:

Formula for mean:

$Mean=\dfrac{\text{Sum of observations}}{\text{Number of observation}}$

The mean of set of a is:

$Mean=\dfrac{200+104+100+160}{4}$

$Mean=\dfrac{564}{4}$

$Mean=141$

The mean of set of b is:

$Mean=\dfrac{270+400+483+300+x}{5}$

$Mean=\dfrac{1453+x}{5}$

It is given that,

Mean of set a: mean of set b= 3:8

$\dfrac{141}{\dfrac{1453+x}{5}}=\dfrac{3}{8}$

$\dfrac{705}{1453+x}=\dfrac{3}{8}$

$8\times 705=3\times (1453+x)$

$5640=4359
+3x$

Isolate the variable x.

$5640-4359
=3x$

$1281
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Divide both sides by 3.

$\dfrac{1281}{3}
=x$

$427
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Therefore, the value of x is 427.

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2 years ago

I write out all the whole numbers, starting from 1. If I wrote 1994 digits altogether, what was the last complete number I wrote

Nataly_w [17]

Answer:

You wrote the numbers from 1 to 9: 9 digits.

You wrote the numbers from 10 to 99: 90*2 = 180 digits.

You have written 189 digits.

Then you wrote another 1994 - 189 = 1805

All the numbers from 100 to 999 have 3 digits

So you wrote 1805/3 = 601 2/3

This means 601 full numbers and 2 digits from the 602. number.

So 100 + 601 - 1 = 700 was the last number you wrote.

Do you agree?

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3 years ago

The low temperature in Anchorage, Alaska, one day was -9 degrees F. On the same day, the low temperature in Flagstaff, Arizona,

matrenka [14]

26>-9

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3 years ago

What is the measure in radians for the central angle of a circle whose radius is 6 cm and intercept arc length is 5. 4 cm?

Vedmedyk [2.9K]

Ok, so find circumference
arc/circumferece=xrad/2pirad

c=2pir
c=2pi6
c=12pi
arc=5.4cm

5.4/12pi=x/2pi
tims both sides by 2pi
5.4/6=x
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3 years ago