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Degger [83]
3 years ago
13

When do you find an area or volume by separating the figure into smaller figures?

Mathematics
1 answer:
brilliants [131]3 years ago
6 0
The question is not defined very well so if u would repeat it
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Perform the indicated operation. x/2+y/3-z/4
weeeeeb [17]

\bf \cfrac{x}{2}+\cfrac{y}{3}-\cfrac{z}{4}\implies \stackrel{\textit{using the LCD of 12}}{\cfrac{(6)x~~+~~(4)y~~-~~(3)z}{12}}\implies \cfrac{6x+4y-3z}{12}

3 0
3 years ago
Read 2 more answers
Three vertices of parallelogram ABCD are A(−2, −2), B(2, 1), and C(0, 7). What are the coordinates of vertex D?
Alinara [238K]
C
you have the 2 side ones and the top one, you are missing the bottom vertice
5 0
3 years ago
Multiply the following rational expressions and simplify the result
GarryVolchara [31]

Answer:

Step-by-step explanation:

We have to solve the given expression,

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y} = \frac{-y(-9+33y+3y^3)}{100-49y^2}.\frac{7y^2+17y+10}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{7y^2+10y+7y+10}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{y(7y+10)+1(7y+10)}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{(y+1)(7y+10)}{14y(y+2)}

                                   = \frac{-3y(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14y(y+2)}

                                   = \frac{-3(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14(y+2)}

                                   = \frac{3(3-11y-y^3)(y+1)}{(10-7y)(14(y+2)}

3 0
3 years ago
What are the solutions to the equation?
Maru [420]

rearrange the equation to where you set it equal to 0 by moving the 25 over.

n2 - 8n -9 = 0

now factor

(n-9)(n+1)

so n1 = 9

n2 = -1

6 0
3 years ago
2. The student council is sponsoring a concert as
Jlenok [28]

Answer:

80 adults must addent to make a complete $1,000

Step-by-step explanation:

You start with the students, $3 for each and 200 of them attend. 3x200=600 dollars in total. Then you would subtract 600 from 1,000. Next you will do the adults, 5x80=400 (The "leftover" cash) $5 for each times 80 adults will be $400 in total.

8 0
3 years ago
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