1. 5 Burgers and 3 orders of fries cost $34. 4 Burgers and 4 orders of fries cost $32. How much does each burger and each order of fries cost? 2. A pile of 44 coins is made up of pennies, nickels, and dimes. If the pile is worth $3.07 and there are twice as many nickels as pennies, how many of each coin does the pile contain?
1 answer:
Answer:
1.
a burger costs $5
an order of fries costs $3
2.
7 pennies
14 nickels
23 dimes
Step-by-step explanation:
x = price of a burger
y = price of a order of fries
5x + 3y = 34
4x + 4y = 32
=>
x + y = 8
x = 8-y
5×(8-y) + 3y = 34
40 - 5y + 3y = 34
-2y = -6
y = $3
x = 8 - 3 = $5
x = number of pennies
y = number of nickels
z = number of dimes
0.01×x + 0.05×y + 0.1×z = 3.07
y = 2x
x + y + z = 44
x + 2x + z = 44
3x + z = 44
z = 44 - 3x
0.01×x + 0.05×2x + 0.1×z = 3.07
0.11×x + 0.1×z = 3.07
0.11×x + 0.1×(44-3x) = 3.07
11x + 10×(44-3x) = 307
11x + 440 - 30x = 307
-19x = -133
x = 7
y = 2×7 = 14
z = 44 - 3×7 = 44 - 21 = 23
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Answer:
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and the last one should be 2/2 , 1. , 100%
Answer:
Step-by-step explanation:
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x = [(log243/log3)-3]/2
x = (5-3)/2
x = 2/2
x = 1
Check:
3^2(1)+3 = 243
3^2+3 = 243
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3×3×3×3×3 = 243
9×9×3 = 243
81×3 = 243
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Answer:
pretty sure it is c but might wrong
Step-by-step explanation:
Answer: A
Step-by-step explanation:
I think it is A because p*(10-2). Can = (p*10)-(p*2)