F=9/5C+32
rewrite as 9/5C+32=F
9/5C+32-32=F-32
9/5C=F-32
(5*9/5)C=(F-32)*5
9C=5F-160
9/9C=(5F-160)/9
C=(5F-160)/9
I think so all the numbers on the to row are even except 8
Answer:
Solution : Third Option
Step-by-step explanation:
The first step here is to make all the signs uniform. As you can see the third inequality has a less than sign, which we can change to a greater than sign by dividing negative one on either side, making the inequality y > - 7.

Now take a look at the third option. Of course the y - coordinate, 3, is greater than - 7, so it meets the third requirement ( y > - 7 ). At the same time 3 > 1( 2 ) > 2, and hence it meets the second requirement as well. 3 > - 3( 1 ) + 4 > - 3 + 4 > 1, meeting the first requirement.
Therefore, the third option is a solution to the system.
Answer:
J
Step-by-step explanation:
Mn=PQ
SAS requires 2 sides and you need to know that they are congruent
Recall that the diagonals of a rectangle bisect each other and are congruent, therefore:

Substituting the given expression for each segment in the first equation, we get:

Solving the above equation for x, we get:

Substituting x=10 in the equation for segment EI, we get:

Therefore:

Now, to determine the measure of angle IEH, we notice that:

therefore,

Using the facts that the triangles are right triangles and that the interior angles of a triangle add up to 180° we get:

<h2>Answer: </h2>