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ryzh [129]
4 years ago
15

What is the volume of a cylinder whose circumfrence of 2 and heigth of 204?

Mathematics
1 answer:
True [87]4 years ago
8 0
Volume = πr²h

circumference = 2πr = 2,   Height, h = 204

2πr = 2

πr = 2/2

πr = 1

r = 1/π

Volume = πr²h = π*(1/π)² * 204 = 204/π

Volume =  204/π   cubic length or ≈ 64.935 cubic length

I hope this helps.
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Subtract the second equation from the first. A)12x=22 B) 4x=6 C) 6y=22 D) -6y=6
Nimfa-mama [501]

Answer:

B) 4x = 6

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Evaluate the step function for the given input values. g(x) = g(2) = g(–2) = g(5) =
romanna [79]

Answer:

Step-by-step explanation:

g(2) = g(–2) = g(5) is never true for the step function.  One " = " symbol per pair of g values, please.

The step function, which you're calling "g(x)," is 0 from -infinity up to but not including 0.  It's 1 from x just greater than 0 through infinity.

Thus:

g(2) = 1 because x is greater than 0.

g(-2) = 0 because x is less than 0.

g(5) = 1 because x is greater than 0.

4 0
3 years ago
when a pen is sold at a discount of 15%, there is a gain of Rs 10. but if it is sold at 25% discount, there is a loss of Rs 2. f
LenaWriter [7]

Answer:

Rs 120.  

Step-by-step explanation:

10=0.85SP-CP; CP+10=0.85SP; SP=[CP+10]/0.85 Eq 1. Let SP= Selling Price and CP= Cost Price

-2 =0.75SP-CP; 0.75SP=C-2; SP=[CP-2]/0.75 Eq 2

[CP+10]/0.85=[CP-2]/0.75 : SP of Eq 1=SP of Eq 2

0.75[CP+10]=0.85[CP-2]

0.75CP+7.5=0.85CP-1.7

0.85CP-0.75CP=-1.7–7.5=9.2

0.10CP=9.2; CP=9.2/0.10

CP=Rs 92 Cost Price of pen

10=0.85SP-92; 0.85SP=92+10=102; SP=102/0.85=Rs 120 Marked Price of pen (answer)

From Eq2: -2=0.75SP-CP; 0.75SP=CP-2=92–2=90; SP=90/0.75=Rs120; -2=0.75(120)-CP; CP-2=0.75(120); CP-2=90; CP=90+2=Rs 92

Set CP of Eq 1=CP of Eq 2:

CP=0.85SP-10 from Eq 1; CP=0.75SP+2 from Eq 2;

0.85SP-10=0.75SP+2; 0.85SP-0.75SP=10+2=12

0.10SP=12; SP=12/0.10=Rs120 is the Marked Price(answer)

Normally, the Selling Price is the marked price. The seller will not disclose the Cost Price because it is the price when the item was acquired or procured, otherwise the buyer will ask for more discounts and based his buying price from the Cost Price if it is known. The calculated SP and CP satisfy both Eq 1 and Eq 2. Both Eq 1 and Eq 2 satisfy the given conditions of the problem above.

8 0
3 years ago
What is the difference in speed between two cars when one traveled 175 km in 4 hours and the other traveled the same distance in
vovangra [49]
<h3>Given :</h3>
  • Distance = 175
  • Time 1 = 4 hours

\\  \\

<h3>To find:</h3>
  • Different between two speeds when distance is same.

\\  \\

<h3>Solution:</h3>

<u>Part</u><u> </u><u>1</u><u> </u><u>:</u>

In first part we will find speed 1 in which time is 4 hours

we know:-

\bigstar \boxed{ \rm speed =  \frac{distance}{time} }

So:-

\dashrightarrow\sf speed_1 =  \dfrac{distance}{time_1}

\\  \\

\dashrightarrow\sf speed_1 =  \dfrac{175}{4}

\\  \\

\dashrightarrow\bf speed_1 =  43.75 \: km {h}^{ - 1}

<u>Part 2</u>

In first part we will find speed 2 in which time is 3 hours

Again:

\bigstar \boxed{ \rm speed =  \frac{distance}{time} }

\\  \\

\dashrightarrow\sf speed_2 =  \dfrac{distance}{time_2}

\\  \\

\dashrightarrow\sf speed_2 =  \dfrac{175}{3}

\\  \\

\dashrightarrow\bf speed_2 = 58.33kmh^{-1}

\\  \\

<u>Part 3</u>

In this part we will find different between speed 1 and speed 2

\bigstar  \boxed{\rm Difference = speed_2 - speed_1}

\\  \\

So :

\dashrightarrow\sf Difference = speed_2 - speed_1 \\

\\  \\

\dashrightarrow\sf Difference =58.33 - 43.75\\

\\  \\

\dashrightarrow\bf Difference =14.58kmh^{-1}\\

\\  \\

\therefore \underline {\textsf{\textbf{Difference in speed between two cars is \red{14.58km/h}}}}

4 0
3 years ago
-2x - y = -9<br><br>5x -2y = 18<br>Solve as a whole number
nexus9112 [7]

Answer:

x = 4, y = 1

(4, 1)

Step-by-step explanation:

-2x - y = -9

5x -2y = 18

-2x - y = -9

+2x     +2x

-y = 2x - 9

/-1    /-1

y = -2x + 9

5x -2y = 18

5x - 2(-2x + 9) = 18

5x + 4x - 18 = 18

9x - 18 = 18

    + 18   + 18

9x = 36

/9  /9

x = 4

Now, we solve for y:

-2(4) - y = -9

-8 - y = -9

+ 8     +8

-y = -1

/-1  /-1

y = 1

(x, y) -> (4, 1)

Hope this helps!

6 0
3 years ago
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