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4 years ago

What is necessary for differentiation to occur in a planet?

Physics

1 answer:

Vesnalui [34]4 years ago

3 0

Answer: A difference in properties between two interacting systems as explained below.

Explanation: Planetary differentiation is the process of separation of different parts of a planetary body as a result of their physical or chemical behavior.

Causes for Physical Differentiation:

1. Melting and crystallization of source rock.

2. Differences in densities

3. Thermal diffusion

4. Collision of large bodies

Chemical Differentiation accounts for differences in chemical compositions of different materials.

The differentiation, or organization, of the Earth into layers led to the formation of a core, a crust, and eventually continents. The light elements were driven from the interior to form an ocean and atmosphere.

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Can the mass of an object is measured by a scale?

Norma-Jean [14]

Answer: In physics, mass is not the same as weight, even though mass is often determined by measuring the object's weight using a spring scale, rather than balance scale comparing it directly with known masses.

Explanation:

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3 years ago

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A conveyer belt carries a load of mass 180kg n lift it up in 1

nalin [4]

Answer:

Cool.

Explanation:

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3 years ago

A toy race car travels down a 25cm ramp in 5 seconds. Calculate its speed. A. 125 cm/sec B. 5 cm/sec C. 0.2 cm/sec D. 20 cm/sec

kipiarov [429]

This would be B, 5cm/sec.
To get this answer you would need to divided 25 which is how large the ramp is, and 5 seconds, the amount of time it took to travel down the ramp.

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3 years ago

Questions on the photo

White raven [17]

Answer:

Option C: Third Class

Explanation:

This is third class because the effort or the input force is in the middle between the fulcrum and the load.

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3 years ago

A track star in the broad jump goes into the jump at 12 m/s and launches himself at 20° above the horizontal. How long is he in

emmainna [20.7K]

Explanation:

It is given that,

Initial speed of the broad jump, u = 12 m/s

It is launched at an angle of 20 degrees above the horizontal. Let t is the time for which the track star i in the air before returning to Earth. The motion of the track star in the broad jump can be treat as the projectile motion. The time of flight of the projectile is given by :

$t=\dfrac{2u\ sin\theta}{g}$

Putting all the values in above equation as :

$t=\dfrac{2\times 12\times \ sin(20)}{9.8}$

t = 0.837 seconds

So, the time for which the track star is in air is 0.837 seconds. Hence, this is the required solution.

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3 years ago