- Initial velocity=0m/s=u
- Acceleration=a=5.5m/s^2
#8.1
#8.2
Use third equation of kinematics
Answer:
The new volume is
Explanation:
<h3> This problem is on the application of Boyle's law which states that" the volume of a given mass of gas at constant temperature is inversely proportional to the pressure"</h3>
Given data
initial pressure p1= 100atm
initial volume v1= 3.7L
final pressure p2= 32 atm
final volume v2= ?
Apply Boyle's law we have
Substituting our data we have
The new volume is
Answer:
2 m/s²
Explanation:
Acceleration is change in velocity over change in time.
a = Δv / Δt
a = (18 m/s − 10 m/s) / 4 s
a = 2 m/s²
The speed should be slower at the top of the ramp and gain speed toward the bottom of the ramp
Answer:
The final speed will be 8.02 rad/s.
Explanation:
Given that
radius ,r=5.9 m
Total acceleration = 18
Tangential acceleration = 12
Here particle is moving in circular path with varying linear speed.So there will be two acceleration ,one is radial acceleration and other one is tangential acceleration.
12=α x 5.9
ω=2.2 rad/s
θ=2πn
θ=2 x π x 1/8 rad
θ=π /4 rad
So the final speed will be 8.02 rad/s.