All categories

3 years ago

Questions on the photo

Physics

1 answer:

White raven [17]3 years ago

8 0

Answer:

Option C: Third Class

Explanation:

This is third class because the effort or the input force is in the middle between the fulcrum and the load.

You might be interested in

Which of these best describes how an appropriate star chart is selected to locate objects in the sky

Umnica [9.8K]

There are no good descriptions on that list.

4 0

3 years ago

A magnetic field is applied to a freely floating uniform iron sphere with radius R = 2.00 mm. The sphere initially had no net ma

grigory [225]

Answer:

$\omega=4.2704*10^-^5 rad/s$

Explanation:

Angular Momentum Formula For atoms= $L_{atom}=0.12Nm_{s}h$

Where:

m_{s}h is the momentum for one atom (m_s is the spin quantum number)

N is the number of atoms= $\frac{N_{A}*m}{M}$

Where:

N_A is Avogadro Number

m is the mass of sphere

M is the molar mass of iron

Angular Momentum Formula For atoms will be= $L_{atom}=0.12\frac{N_{A}m}{M} m_{s}h$

Angular Momentum of Sphere= $L_{sphere}=I\omega$

where:

$I=\frac{2mR^{2}}{5}$

So,Angular Momentum of Sphere= $L_{sphere}=\frac{2mR^{2}}{5}\omega$

Angular Momentum of sphere=Angular Momentum of atoms

$L_{sphere}$ = $L_{atom}$

$\frac{2mR^{2}}{5}\omega$ = $0.12\frac{N_{A}m}{M} m_{s}h$

For iron, $m_s =\frac{1}{2}$ . So above equation will become:

$\omega=\frac{0.12*5*N_{A}h}{4*M*R^{2} }$

Where R=2mm, M=0.0558Kg/mol (Molar Mass of iron),h=Planck's Constant/2π

$\omega=\frac{0.12*5*(6.022*10^{23})(6.63*10^{-34}/2*\pi)}{4*0.0558*(2*10^{-3})^{2}}$

$\omega=4.2704*10^-^5 rad/s$

5 0

3 years ago

WORTH 50 POINTSSSS!!!!!!!! don't lie either if you do I will report your answer and get my points back idc !!!!!!

BARSIC [14]

Answer:

Explanation:

3 0

3 years ago

How is humidity related to air pressure?

Vlad [161]

Humid air has higher pressure because of the heaviness of the water

7 0

4 years ago

Read 2 more answers

20 pts !!!!

garri49 [273]

Am not really sure but what i see is D

4 0

3 years ago