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3 years ago

What could people do to DECREASE erosion of the Earth’s surface?

1 answer:

4 0

Stop doing so much construction. When construction workers built highways they build it on top of a small man-made mountain and then set the road on top and put the grass on the dirt leaving the sides to erode overtime. But don't forget the bottom, underneath the bridge when you drive out there are two columns that slowly decrease and are not always patched by brakes to keep from eroding, but when storms and heavy winds come, it will wash away.

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Each element has a unique name. How else can

Otrada [13]

Answer:

C. by its chemical Symbol

Hope this helps!

5 0

3 years ago

0.0200 M Fe3+ is initially mixed with 1.00 M oxalate ion, C2O42-, and they react according to the equation: Fe3+(aq) + 3 C2O42-(

Studentka2010 [4]

Answer : The concentration of $Fe^{3+}$ at equilibrium is 0 M.

Solution : Given,

Concentration of $Fe^{3+}$ = 0.0200 M

Concentration of $C_2O_4^{2-}$ = 1.00 M

The given equilibrium reaction is,

$Fe^{3+}(aq)+3C_2O_4^{2-}(aq)\rightleftharpoons [Fe(C_2O_4)_3]^{3-}(aq)$

Initially conc. 0.02 1.00 0

At eqm. (0.02-x) (1.00-3x) x

The expression of $K_c$ will be,

$K_c=\frac{[[Fe(C_2O_4)_3]^{3-}]}{[C_2O_4^{2-}]^3[Fe^{3+}]}$

$1.67\times 10^{20}=\frac{(x)^2}{(1.00-3x)^3\times (0.02-x)}$

By solving the term, we get:

$x=0.02M$

Concentration of $Fe^{3+}$ at equilibrium = 0.02 - x = 0.02 - 0.02 = 0 M

Therefore, the concentration of $Fe^{3+}$ at equilibrium is 0 M.

4 0

3 years ago

Which one of the following is not equal to 100 meters?

julsineya [31]

10 hectometers

One hectometer is 100 meters in length already, so 10 is 1000

3 0

3 years ago

In which of the following is number of electrons the ion contains given correctly? A. H+ has 1 electron. B. Br- has 34 electrons

Leviafan [203]

The correct answer would be D. Ca^2+ has 18 electrons. This is because 2+ means that 2 electrons have been removed, and Ca starts out with 20 electrons. As 20 - 2 = 18 electrons, D is the correct answer.

Hope this helps!

8 0

3 years ago

Read 2 more answers

1. The red light associated with the aurora borealis is emitted by excited oxygen atoms. This

stiv31 [10]

Answer:

Frequency = 0.005× 10¹⁷ s⁻¹

E = 0.03 × 10⁻²⁰KJ

Explanation:

Given data:

Wavelength of light = 630.0 nm (630 × 10⁻⁹ m)

Frequency of light = ?

Energy in joule = ?

Solution:

speed of light = wavelength × frequency

Frequency = speed of light / wavelength

Frequency = 3 × 10⁸ m/s / 630 × 10⁻⁹ m

Frequency = 0.005× 10¹⁷ s⁻¹

Energy:

E = h. f

E = 6.63× 10⁻³⁴ Kg. m²/s × 0.005× 10¹⁷ s⁻¹

E = 0.03 × 10⁻¹⁷ j

E = 0.03 × 10⁻¹⁷ j×1 kj /1000 j

E = 0.03 × 10⁻²⁰KJ

4 0

3 years ago