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umka2103 [35]
3 years ago
5

Part A.4 and Part B. In a hurry to complete the experiment, Anna withdrew two volumes of solution from Part A.2 before the preci

pitate had settled. As a result, what dilemma might she have encountered in Part B
Chemistry
1 answer:
Harman [31]3 years ago
6 0

Answer:

Anna may have trouble because of inaccurate results or observations.

<u>Explanation:</u>

In chemistry, a precipitate is an <em>insoluble solid</em> that is gotten from a liquid solution. Because Anna withdrew two volumes of solution from Part A.2 before the precipitate had settled she may find it difficult to determine the limiting reactant; that is the chemical element or substance that limits the amount of product made during the chemical reaction because some precipitate was captured with the liquid lying above, which when adding the reagent, will not show the difference between them.

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____________  was the first chemist to organize elements by atomic number
Natalija [7]

Answer:

Henry Moseley

Explanation: Passed with 98

4 0
3 years ago
Natural gas is stored in a spherical tank at a temperature of 13°C. At a given initial time, the pressure in the tank is 117 kPa
drek231 [11]

Answer:

1.  the absolute pressure in the tank before filling = 217 kPa

2. the absolute pressure in the tank after filling = 312 kPa

3. the ratio of the mass after filling M2 to that before filling M1 = 1.44

The correct relation is option c (\frac{M_{2} }{M_{1} } = \frac{P_{2} T_{1} }{P_{1} T_{2} })

Explanation:

To find  -

1. What is the absolute pressure in the tank before filling?

2. What is the absolute pressure in the tank after filling?

3. What is the ratio of the mass after filling M2 to that before filling M1 for this situation?

As we know that ,

Absolute pressure = Atmospheric pressure + Gage pressure

So,

Before filling the tank :

Given - Atmospheric pressure = 100 kPa ,  Gage pressure = 117 kPa

⇒Absolute pressure ( p1 )  = 100 + 117 = 217 kPa

Now,

After filling the tank :

Given - Atmospheric pressure = 100 kPa ,  Gage pressure = 212 kPa

⇒Absolute pressure (p2)  = 100 + 212= 312 kPa

Now,

As given, volume is the same before and after filling,

i.e. V_{1} = V_{2}

As we know that, P ∝ M

⇒ \frac{p_{1} }{p_{2} } = \frac{m_{1} }{m_{2} }

⇒\frac{m_{2} }{m_{1} } = \frac{p_{2} }{p_{1} }

⇒\frac{m_{2} }{m_{1} } = \frac{312 }{217 } = 1.4378 ≈ 1.44

Now, as we know that PV = nRT

As V is constant

⇒ P ∝ MT

⇒\frac{P}{T} ∝ M

⇒\frac{M_{2} }{M_{1} } = \frac{P_{2} T_{1} }{P_{1} T_{2} }

So, The correct relation is c option.

6 0
3 years ago
A container of oxygen with a volume of 60 L is heated from 300 K to 400 k, What is the new volume?
Lunna [17]

Answer:

80L

Explanation:

V1/T1 = V2/T2

V2 = V1 T2/T1

T1 = 300K

V1 = 60L

T2 = 400K

V2 = ?

V2 = V1 T2/T1

V2 = (60L)(400K) / (300K)

V2 = 80L

7 0
2 years ago
Define critical point. Group of answer choices The temperature and pressure below which a supercritical fluid exists. The temper
attashe74 [19]

Answer:

The temperature and pressure below which a supercritical fluid exists.

Explanation:

Critical point is a region on the phase diagram where fluid phases (liquids and gases) have the equal density.

This is caused by increased temperature and pressure of the fluid particles in a confided container. Supercritical fluids exist in a state above critical point.

I hope this explanation was clear.

8 0
3 years ago
Hi, im 15 i live in indiana and i need friends please i love tacos and im an all around fun person but very emotionally drained.
Andrei [34K]

Answer:

you sound like a cool guy, ill email ya one of these days

Explanation:

4 0
3 years ago
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