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umka2103 [35]
3 years ago
5

Part A.4 and Part B. In a hurry to complete the experiment, Anna withdrew two volumes of solution from Part A.2 before the preci

pitate had settled. As a result, what dilemma might she have encountered in Part B
Chemistry
1 answer:
Harman [31]3 years ago
6 0

Answer:

Anna may have trouble because of inaccurate results or observations.

<u>Explanation:</u>

In chemistry, a precipitate is an <em>insoluble solid</em> that is gotten from a liquid solution. Because Anna withdrew two volumes of solution from Part A.2 before the precipitate had settled she may find it difficult to determine the limiting reactant; that is the chemical element or substance that limits the amount of product made during the chemical reaction because some precipitate was captured with the liquid lying above, which when adding the reagent, will not show the difference between them.

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Daniel [21]

Answer: 2.71 moles of solute for every 1 kg of solvent.

Explanation: As you know, the molality of a solution tells you the number of moles of solute present for every 1 kg of the solvent.This means that the first thing that you need to do here is to figure out how many grams of water are present in your sample. To do that, use the density of water.500.mL⋅1.00 g1mL=500. g Next, use the molar mass of the solute to determine how many moles are present in the sample.115g⋅1 mole NanO385.0g=1.353 moles NaNO3So, you know that this solution will contain 1.353moles of sodium nitrate, the solute, for 500. g of water, the solvent.In order to find the molality of the solution, you must figure out how many moles of solute would be present for 1 kg=103g of water.103g water⋅1.353 moles NaNO3500.g water=2.706 moles NaNO3You can thus say that the molality of the solution is equal to molality=2.706 mol kg−1≈2.71 mol kg−1 The answer is rounded to three sig figs.

8 0
3 years ago
What is the [OH-] in a solution with a poh of 3.90
zheka24 [161]

Answer:

7.9433E-3

Explanation:

POH=-log OH

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8 0
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