Answer:
The calculated value Z = 1.39 <1.96 at 0.05 level of significance
The null hypothesis is accepted
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 43
Given that the mean of the sample = 47
Given that the standard deviation of the Population = 25
Given that the sample size 'n' = 76
<u><em>Step(ii):-</em></u>
<u><em>Null hypothesis:H₀: μ = 43</em></u>
<u><em>Alternative Hypothesis: H₁: μ ≠ 43</em></u>
Test statistic
![Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7Bx%5E%7B-%7D-mean%20%7D%7B%5Cfrac%7BS.D%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D)
![Z = \frac{47-43 }{\frac{25}{\sqrt{76} } }](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B47-43%20%7D%7B%5Cfrac%7B25%7D%7B%5Csqrt%7B76%7D%20%7D%20%7D)
Z = 1.39
Level of significance = 0.05
The critical value = 1.96
<u><em>Final answer:-</em></u>
<em>The calculated value Z = 1.39 <1.96 at 0.05 level of significance</em>
<em>The null hypothesis is accepted </em>