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3 years ago

1. What is 26% written as a decimal?

Mathematics

2 answers:

Pani-rosa [81]3 years ago

7 0

Answer:

26% = 0.26 in decimal form

Step-by-step explanation:

You just put a 0. in front of it,

take .26

Then 100 = 1.00

and 26 = .26

Hope This Helps:)

Would appreciate brainliest!!:)

sattari [20]3 years ago

5 0

Answer:

.26 = 26% hope this helps! :)

Step-by-step explanation:

.26

100 = 1.00

26 = .26

you just move the decimal point over 2

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Round 713,923 to the nearest hundred.

jeyben [28]

Answer:

713,7923 to the nearest hundred is 713,900

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3 years ago

Allyson and Adrian have decided to connect their ankles with a bungie cord; one end is tied to each person's ankle. The cord is

BARSIC [14]

Answer: 5.5 seconds

Step-by-step explanation:

30=5/4 ×(-20) + 10t

30 =-25 +10t

10t=55

t=5.5seconds

The cord will first touch the corner of the building after 5.5secs

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3 years ago

A bedroom door in the house has the same dimension as the front door but the length is 30 inches rather than 36 inches how much

arsen [322]

Answer:

6/5

Step-by-step explanation:

Calculate the volume by multiplying the measured length and width of the space together, then multiply the result by the height of the room. From the example, 10 * 25 feet = 250 square feet, and 5 * 10 feet = 50 square feet.

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2 years ago

The cost y (in dollars) to rent a pickup truck is proportional to the number x of hours that the pickup truck is rented. It cost

gulaghasi [49]

25 dollars for each hour.

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3 years ago

Find the differential coefficient of <br><img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^

Gemiola [76]

Answer:

$\rm \displaystyle y' = 2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x}$

Step-by-step explanation:

we would like to figure out the differential coefficient of $e^{2x}(1+\ln(x))$

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

$\displaystyle y = {e}^{2x} \cdot (1 + \ln(x) )$

to do so distribute:

$\displaystyle y = {e}^{2x} + \ln(x) \cdot {e}^{2x}$

take derivative in both sides which yields:

$\displaystyle y' = \frac{d}{dx} ( {e}^{2x} + \ln(x) \cdot {e}^{2x} )$

by sum derivation rule we acquire:

$\rm \displaystyle y' = \frac{d}{dx} {e}^{2x} + \frac{d}{dx} \ln(x) \cdot {e}^{2x}$

Part-A: differentiating $e^{2x}$

$\displaystyle \frac{d}{dx} {e}^{2x}$

the rule of composite function derivation is given by:

$\rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dg} f(g(x)) \times \frac{d}{dx} g(x)$

so let g(x) [2x] be u and transform it:

$\displaystyle \frac{d}{du} {e}^{u} \cdot \frac{d}{dx} 2x$

differentiate:

$\displaystyle {e}^{u} \cdot 2$

substitute back:

$\displaystyle \boxed{2{e}^{2x} }$

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

$\displaystyle \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)$

let

$f(x) \implies \ln(x)$
$g(x) \implies {e}^{2x}$

substitute

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \frac{d}{dx}( \ln(x) ) {e}^{2x} + \ln(x) \frac{d}{dx} {e}^{2x}$

differentiate:

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \boxed{\frac{1}{x} {e}^{2x} + 2\ln(x) {e}^{2x} }$

Final part:

substitute what we got:

$\rm \displaystyle y' = \boxed{2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x} }$

and we're done!

6 0

3 years ago