What is the distance in units between (−11, −20) and (−11, 5)

Mathematics

2 answers:

WARRIOR [948]3 years ago

8 0

Answer:

The distance is $25\ units$

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Let

$A(-11,-20)\\B(-11,5)$

substitute the values

$d=\sqrt{(5+20)^{2}+(-11+11)^{2}}$

$d=\sqrt{(25)^{2}}$

$d=25\ units$

Morgarella [4.7K]3 years ago

6 0

Distance = √(x₂-x₁)² + (y₂-y₁)²
d = √(-11-(-11)) + (5-(-20))²
d = √0² + 25²
d = √625
d = 25

In short, Your Answer would be 25 units

Hope this helps!

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Note 1: A more general solution is $y = Ce^x$ for some constant C.
Note 2: It might be tempting to say the general solution is $y = e^x+C$ , but that is not the case because $y = e^x+C \to y' = e^x+0 = e^x$ and we can see that $y' = y$ would only be true for C = 0, so that is why $y = e^x+C$ does not work.