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4 years ago

What is the distance in units between (−11, −20) and (−11, 5)

Mathematics

2 answers:

WARRIOR [948]4 years ago

8 0

Answer:

The distance is $25\ units$

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Let

$A(-11,-20)\\B(-11,5)$

substitute the values

$d=\sqrt{(5+20)^{2}+(-11+11)^{2}}$

$d=\sqrt{(25)^{2}}$

$d=25\ units$

Morgarella [4.7K]4 years ago

6 0

Distance = √(x₂-x₁)² + (y₂-y₁)²
d = √(-11-(-11)) + (5-(-20))²
d = √0² + 25²
d = √625
d = 25

In short, Your Answer would be 25 units

Hope this helps!

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How many observations are there for each case in a t test for dependent samples?

Oxana [17]

The number of observations for each case in a t test for dependent samples is two is the correct answer.

In this question,

The dependent t-test also called the paired t-test or paired-samples t-test compares the means of two related groups to determine whether there is a statistically significant difference between these means. Each sample must be randomly selected from a normal population and each member of the first sample must be paired with a member of the second sample.

A dependent samples t-test uses two raw scores from each person to calculate difference scores and test for an average difference score that is equal to zero.

The groups contain either the same set of subjects or different subjects that the analysts have paired meaningfully. In dependent samples, subjects in one group do provide information about subjects in other groups.

Hence we c an conclude that the number of observations for each case in a t test for dependent samples is two is the correct answer.

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2 years ago

Find a fraction that is bigger than ⅚, but smaller than 6/7. Show how you did it!!

jek_recluse [69]

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3 years ago

(3y^0 x^2)^6 times y^-3 zx8

timurjin [86]

Ok so some basic rules

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so
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$[(3(1)x^2)^6][y^{-3}zx^8]$
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3 years ago

PLEASE HURRY!! simplify completely show all work for full credit

Irina18 [472]

Answer:

$4x^{3}$

Step-by-step explanation:

Given:

$(\frac{192x^{12}}{3x^{3}} )^{\frac{1}{3}}$

Apply exponent rule of distribution:

$\frac{(192x^{12})^{\frac{1}{3}}}{(3x^{3})^{\frac{1}{3}}}$

Simplify the numerator:

$\\\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{(3x^{3})^{\frac{1}{3}}}$

Simplify the denominator:

$\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{3^\frac{1}{3}x}}$

Simplify:

$4x^{3}$

-> To explain this party since it is a bigger jump, $3^{\frac{1}{3}}x$ is on the top and the bottom, so it becomes a one. We are left with a four on the top, and using properties of exponents 4 - 1 = 3, explaining why we have $x^{3}$ leftover too.