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Lubov Fominskaja [6]
3 years ago
8

Simplify: –4(x – 2) – 5(y + 2) + (–3)(8 – 6b)

Mathematics
2 answers:
WARRIOR [948]3 years ago
8 0
-4(x-2)-5(y-2)+(-3)(8-6b)
-4(x-2)-5(y-2)+(-24+18b)
-4x+8-5y+10-24+18b
-4x-5y+18b+8+10-24
-4x-5y+18b+18-24
-4x-5y+18b-6
So it is the second one.

Hope this helps :)
Tamiku [17]3 years ago
7 0
Yur answer isD.–4x – 5y + 18b – 26

hope it helpes
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Construct the 90% confidence interval for the proportion of students at the college who have completed their required English 10
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Answer:

The confidence interval has an lower limit of \pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}} and an upper limit of \pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}, in which \pi is the sample proportion and n is the size of the sample.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}}

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}

The confidence interval has an lower limit of \pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}} and an upper limit of \pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}, in which \pi is the sample proportion and n is the size of the sample.

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Answer:

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Step-by-step explanation:

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Carter invested $16,000 in an account paying an interest rate of 5.6% compounded monthly. Assuming no deposits or withdrawals ar
jenyasd209 [6]

Answer:

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Step-by-step explanation:

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