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VARVARA [1.3K]
3 years ago
10

How can you tell if a compound is a solid, liquid, gas, or aqeous.

Chemistry
1 answer:
Andre45 [30]3 years ago
4 0
<span>aqueous is the colorful one</span>

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Horizontal lines that represent different climate zones are called
Neporo4naja [7]

Answer:

Horizontal lines that represent different climate zones are called latitude.

Explanation:

Latitude is the distance that exists between a point on the Earth's surface to the equator, counted by the degrees of its meridian. That is, it is the distance, measured in degrees, that exists between any parallel and the line of the Equator. The latitude of a point is measured to the North or South of the zero parallel and its value can vary between 0 ° from the equator to 90 ° N from the North pole or 90 ° from the South pole.

Climate is related to latitude because it sets the amount of solar energy that a given region or place receives. Places located at high latitudes (far from the Ecuador) receive less sunlight than places located at low latitudes (near the Equator). Thus, cities distant from the equator and close to the poles have a cold climate, while at low altitudes there are high temperatures and a hot or tropical climate.

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Look at the following data provided below:
Vlad1618 [11]

Considering the Hess's Law, the enthalpy change for the reaction is -84.4 kJ.

<h3>Hess's Law</h3>

Hess's Law indicates that the enthalpy change in a chemical reaction will be the same whether it occurs in a single stage or in several stages. That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

<h3>Enthalpy change for the reaction in this case</h3>

In this case you want to calculate the enthalpy change of:

2 C (graphite) + 3 H₂(g) → C₂H₆(g)

which occurs in three stages.

You know the following reactions, with their corresponding enthalpies:

Equation 1: C₂H₆(g) + \frac{7}{2} O₂(g) → 2 CO₂(g) + 3 H₂O(l) ; ΔH° = –1560 kJ

Equation 2:  H₂(g) + \frac{1}{2} O₂(g) → H₂O(l) ; ΔH° = –285.8 kJ

Equation 3: C(graphite) + O₂(g) → CO₂(g) ; ΔH° = –393.5 kJ

Because of the way formation reactions are defined, any chemical reaction can be written as a combination of formation reactions, some going forward and some going back.

In this case, first, to obtain the enthalpy of the desired chemical reaction you need 2 moles of C(graphite) on reactant side and it is present in third equation. In this case it is necessary to multiply it by 2 to obtain the necessary amount. Since enthalpy is an extensive property, that is, it depends on the amount of matter present, since the equation is multiply by 2, the variation of enthalpy also.

Now, you need 3 moles of H₂(g) on reactant side and it is present in second equation. In this case it is necessary to multiply it by 3 to obtain the necessary amount and the variation of enthalpy also is multiplied by 3.

Finally, 1 mole of C₂H₆(g) must be a product and is present in the first equation. Since this equation has 1 mole of C₂H₆(g) on the reactant side, it is necessary to locate the C₂H₆(g) on the reactant side (invert it). When an equation is inverted, the sign of delta H also changes.

In summary, you know that three equations with their corresponding enthalpies are:

Equation 1:  2 CO₂(g) + 3 H₂O(l) → C₂H₆(g) + \frac{7}{2} O₂(g); ΔH° = 1560 kJ

Equation 2:  3 H₂(g) + \frac{3}{2} O₂(g) → 3 H₂O(l) ; ΔH° = –857.4 kJ

Equation 3: 2 C(graphite) + 2 O₂(g) → 2 CO₂(g) ; ΔH° = –787 kJ

Adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

2 C (graphite) + 3 H₂(g) → C₂H₆(g)    ΔH= -84.4 kJ

Finally, the enthalpy change for the reaction is -84.4 kJ.

Learn more about enthalpy for a reaction:

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#SPJ1

7 0
2 years ago
PLEASE ANSWER ASAP
kodGreya [7K]

Answer:It is C i got it correct

Explanation:

7 0
3 years ago
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