Question

At a time denoted as t=0, a student carrying a new flu virus comes back to an isolated campus that has a fixed number of 1000 people. Determine a differential equation for the number of people x(t) who have contracted the flu if the rate at which the disease spreads is proportional to the number of interactions between the people who have the flu and the number of people who have not yet been exposed to it. (Please use k as the proportional constant.)

Answer 1

Answer:

$\dfrac{dx(t)}{dt} = kx(t)[1000-x(t)], x(0)=0$

Step-by-step explanation:

Total Number of People on Campus =1000

Let the number of people who have contracted the flu =x(t)

Therefore, the number of people who have not contracted the flu =1000-x(t)

Since the rate at which the disease spreads is proportional to the number of interactions between the people who have the flu and the number of people who have not yet been exposed to it.

$\dfrac{dx(t)}{dt} \propto x(t)[1000-x(t)]$

Introducing the proportional constant k, we obtain:

$\dfrac{dx(t)}{dt} = kx(t)[1000-x(t)]$

At t=0, there was no infected on the campus, therefore the initial condition is given:

$x(0)=0$

Therefore, a differential equation for the number of people x(t) who have contracted the flu is:

$\dfrac{dx(t)}{dt} = kx(t)[1000-x(t)], x(0)=0$