Answer:
The answer is 116
Step-by-step explanation:
Because this shape is a quadrilateral, so the sum of the angles of a quadrilateral is a total of 360 degrees. So i added 90 + 90 + 64 = 244. And 360 - 244 = 116.
Answer:
Step-by-step explanation:
The slope of all lines in quadrant 1 is positive. FALSE
The slope of a line does not depend on the quadrant.
The slope of <u>all lines</u> that pass through the origin is undefined.FALSE
The slope of some lines that pass trough the origin are undefined ( lines that are vertical have undefined slope)
The larger the slope, the longer the line.FALSE
The lines do not get longer or shorter because they go to infinity in both directions.
The larger the magnitude of the slope value, the steeper the line. TRUE
The larger the absolute value of the slope the steeper the slope.
Given plane Π : f(x,y,z) = 4x+3y-z = -1
Need to find point P on Π that is closest to the origin O=(0,0,0).
Solution:
First step: check if O is on the plane Π : f(0,0,0)=0 ≠ -1 => O is not on Π
Next:
We know that the required point must lie on the normal vector <4,3,-1> passing through the origin, i.e.
P=(0,0,0)+k<4,3,-1> = (4k,3k,-k)
For P to lie on plane Π , it must satisfy
4(4k)+3(3k)-(-k)=-1
Solving for k
k=-1/26
=>
Point P is (4k,3k,-k) = (-4/26, -3/26, 1/26) = (-2/13, -3/26, 1/26)
because P is on the normal vector originating from the origin, and it satisfies the equation of plane Π
Answer: P(-2/13, -3/26, 1/26) is the point on Π closest to the origin.
The answer is 48.5, did a question similar to this on a quiz and got it right
