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densk [106]
3 years ago
8

Which of the following is a linear function? А B C D

Mathematics
1 answer:
kramer3 years ago
3 0

Answer:

d

Step-by-step explanation:

..................

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Guys plzzz helpp me this gotta be done now!!
Bess [88]

Answer:

I think it's C.

Step-by-step explanation:

plz mark brainliest

5 0
3 years ago
How do you understand it
maks197457 [2]
431 ≈ 400
115 ≈ 100
400 - 100 = 300
3 0
4 years ago
Read 2 more answers
Which number line best represents the solution to the inequality -18x+3<48
Doss [256]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given inequality

-18x+3

STEP 2: Solve for x

\begin{gathered} -18x+3\frac{-45}{18} \\ x>-\frac{5}{2} \\ x>-2.5 \end{gathered}

STEP 3: Plot the number line for that represents the final solution

Hence, the number line that best represents the final solution can be seen in the number line below:

OPTION A

6 0
2 years ago
Given: Lines p and q are parallel and r is a transversal.
qwelly [4]

The statements that would complete the proof where ∠2 ≅ ∠7 by the transitive property are:

∠2 ≅ ∠3

∠3 ≅ ∠7

<h3>What is the Transitive Property?</h3>

The transitive property states that if x = y, and y = z, then x = z.

From the image given below, we have:

∠2 ≅ ∠3 because they are vertical angles which must be congruent.

∠3 ≅ ∠7 because corresponding angles are congruent.

Applying the transitive property, we can state that: ∠2 ≅ ∠7.

Therefore, the statements that would complete the proof are:

  • ∠2 ≅ ∠3
  • ∠3 ≅ ∠7

Learn more about the transitive property on:

brainly.com/question/2437149

#SPJ1

8 0
2 years ago
In a class of P students, the average of test scores is 70. In another class the average test scores is 92. When scores of the t
Basile [38]

So, since averages are defined as:

\frac{\sum_{k=1}^{P} P_k}{P}=70

So, since P are the total number of elements and P_k is the P_kth student. This is saying if we sum over each student's score and divide it by the number of students, we should get P, which is true.

So, using that logic, the other class can be represented as:

\frac{\sum_{k=1}^{N} N_k}{N}=70

We can take both of these equations and multiply them by N:

\sum_{k=1}^{P} P_k=70P

\sum_{k=1}^N N_k=92N

So, if we want to find the average of this we should add both our equations then divide by P+N, which is the number of all the students.

\frac{\sum_{k=1}^{P} P_k+\sum_{k=1}^{N}N_k}{N+P}=\frac{70P+92N}{N+P}

To make this simpler we can replace our LHS with 86, since that's the average of both classes combined.

86=\frac{92N+70P}{N+P} \implies\\ 86N+86P=92N+70P \implies \\ 16P=6N \implies \\ \frac{16P}{N}=6 \implies \\ \frac{P}{N}=\frac{6}{16}

Simplified we would have P/N=3/8.

7 0
4 years ago
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