The x -intercepts occur when f(x) =0
So,
(x-4)^2 = x^2 -8x + 16 -3 =0
x^2 -8x + 13 =0
Solving by the quadratic formula
x1 = 5.7321
x2 = 2.2679
Answer:
number 10
dy/dx =(dy/dt).(dt/dx)
now find
dy/dt=4t-1. , dt/dx=1
so : dy/dx=(4t-1).(1)
dy/dx= 4t-1 ,we have x=t-3-----> t=x+3
subtitute at t
dy/dx= 4(x+3)-1=4x+12-1= 4x+11
Answer:
32=40
26=39
Step-by-step explanation:
Answer: y=5x+3
Step by step explanation:
Perpendicular meaning that the product of the slope/gradient is -1 hence ...
-1/5 * x = -1
x = -1/-1/5
x = 5
The equation perpendicular to y=-1/5x-3 is y=5x-c
Now it contains the points (1,2)
x variable is 1 and y variable is 2 plug them into the line equation
2=5(1)-c
2=5-c
2-5=-c
-3=-c divide by -1
3=c
Hence the perpendicular equation is y=5x+3
Hopefully it’s correct :)
Answer:
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Step-by-step explanation: