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3 years ago

Write a polynomial in standard form with the zeros –4, 0, 1, and 4.

Mathematics

1 answer:

Reptile [31]3 years ago

4 0

Step-by-step explanation:

The answer in the picture above

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2 Points Which of the following is(are) the solution(s) to . x+6 = 2x - 1?

seropon [69]

Answer:

x = 7

Step by step explanation:

minus x on both sides

6 = x -1

add 1 on both sides

x = 7

7 0

3 years ago

Which graph represents the inequality 3y−5x>−6?

Lelechka [254]

Answer:Top Left

Step-by-step explanation:

4 0

3 years ago

Angle 1 measure 75 degree what is its complement

dalvyx [7]

I think it’s 76 because I added it that’s a way i solved it but you can also multiple it by 1 and it will give the the same answer

3 0

3 years ago

1b. $1 6− 1 3 Lin said the value of this expression is $ 1 6. Is she correct? Explain or show your reasoning to prove your an

Brrunno [24]

Answer:

No she is not correct

Step-by-step explanation:

She is not correct because “value of expressions” mean the result which for this it is 16-13 =3 and she is wrong. please mark me brainly! Hope this helps! :D

4 0

3 years ago

the volume v of a right circular cylinder of radius r and heigh h is V = pi r^2 h 1. how is dV/dt related to dr/dt if h is const

laiz [17]

In general, the volume

$V=\pi r^2h$

has total derivative

$\dfrac{\mathrm dV}{\mathrm dt}=\pi\left(2rh\dfrac{\mathrm dr}{\mathrm dt}+r^2\dfrac{\mathrm dh}{\mathrm dt}\right)$

If the cylinder's height is kept constant, then $\dfrac{\mathrm dh}{\mathrm dt}=0$ and we have

$\dfrac{\mathrm dV}{\mathrm dt}=2\pi rh\dfrac{\mathrm dt}{\mathrm dt}$

which is to say, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ are directly proportional by a factor equivalent to the lateral surface area of the cylinder ( $2\pi r h$ ).

Meanwhile, if the cylinder's radius is kept fixed, then

$\dfrac{\mathrm dV}{\mathrm dt}=\pi r^2\dfrac{\mathrm dh}{\mathrm dt}$

since $\dfrac{\mathrm dr}{\mathrm dt}=0$ . In other words, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dh}{\mathrm dt}$ are directly proportional by a factor of the surface area of the cylinder's circular face ( $\pi r^2$ ).

Finally, the general case ( $r$ and $h$ not constant), you can see from the total derivative that $\dfrac{\mathrm dV}{\mathrm dt}$ is affected by both $\dfrac{\mathrm dh}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ in combination.

8 0

3 years ago