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Nataliya [291]
3 years ago
15

Write a polynomial in standard form with the zeros –4, 0, 1, and 4.

Mathematics
1 answer:
Reptile [31]3 years ago
4 0

Step-by-step explanation:

The answer in the picture above

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Select the correct answer from each drop-down menu.
Oksana_A [137]

Answer:

B

Step-by-step explanation:

B because range of set B is more than set A

range B=56-12=44

range A=55-12=43

5 0
2 years ago
Solve the initial value problem. 7y′−4y=e−πt2, y(0)=a Let a0 be the value of a for which the transition from one type of long-ru
densk [106]

Answer:

as shown in the attached file

Step-by-step explanation:

The detailed steps and application of differential equation, the use of integrating factor to generate the solution and to solve for the initial value problem is as shown in the attached file.

8 0
2 years ago
The Martin family's truck gets an average of 25 miles per gallon. Predict how many milrs they can drive using 7 gallons of gas.
Hunter-Best [27]
Okay so on average if they can go 25 miles per gallon that would mean you could just multiply 25 and 7 to get 175. So on average they could go 175 miles on 7 gallons of gas. Keep in mind that the answer can and will change depending on traffic, how fast or slow they are going, and if they are traveling behind a big-rig that moves more air that would normally be putting pressure on the car to push out of the way  but the big-rig helps save gas but it can also waste more gas if they are driving slower then normal.
Sorry for the extra information once I start it's hard to stop. Any way I hope this helps.
8 0
3 years ago
How do you write 4 out of ten as a decimal?
Elodia [21]
4 out of 10 (or 4/10) is written as .4 as a decimal. This is because when you divide 4 by 10, you get .4
7 0
2 years ago
Read 2 more answers
A) how many ways are there to choose 10 players to take the field?
Kruka [31]

A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.

B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4. (13−10)! 3!

C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =

10! 3!

9!1! 1!2! 10! 3!

8!2! 2!1! 10! 3!

7!3! 3!0!

= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =

= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =

= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285 1·2·3

<span>possible choices.</span><span> 
</span>

  


5 0
3 years ago
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